1. Suppose you mix 21.0 g of water at 52.7° C with 54.9 g of water at 31.5° C in an insulated cup. What is the maximum temperature of the water after mixing?

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Heat and Enthalpy Solved Problems
1. Suppose you mix 21.0 g of water at 52.7° C with 54.9 g of water at 31.5°
C in an insulated cup. What is the maximum temperature of the water
after mixing?
Answer:
Asystem = -4surroundings
Яhot H,0 — -Ясоol H20
Тhot H,0Chot н,047hot H,0 3 -тсоol H20Ссol H,047cоol H,0
>(4.184)aTnot H,0 = -(54.9 g) (4.184 )
AThot H,0 =-
ΔΙ cool H2O
°C
87.86 )ATrot Hz0 = (229.702) ATe
сool Hz0
AThot H,0 = (2.614)ATcool H20
Tf - 52.7°C = 2.614T; – 31.5°C
2.614T; :
= 21.2°C
Tf =
= 8.11°C
Heat and Enthalpy Solved Problems
2. Use the information provided to determine AH°rxn for the following
reaction
3 Fe203 (s) + CO (g) → 2 Fe304 (s) + CO2 (g)
ΔΗ ?
rxn
ΔΗ'
Fe203 (s)
Fe304 (s)
CO (g)
CO2 (g)
-824 kJ/mol
-1118 kJ/mol
-111 kJ/mol
-394 kJ/mol
Answer:
kJ
(-824-
mol
kJ
+ -111
mol)
kJ
1118·
mol
kJ
+ -394.
mol)
kJ
577
mol
Transcribed Image Text:Heat and Enthalpy Solved Problems 1. Suppose you mix 21.0 g of water at 52.7° C with 54.9 g of water at 31.5° C in an insulated cup. What is the maximum temperature of the water after mixing? Answer: Asystem = -4surroundings Яhot H,0 — -Ясоol H20 Тhot H,0Chot н,047hot H,0 3 -тсоol H20Ссol H,047cоol H,0 >(4.184)aTnot H,0 = -(54.9 g) (4.184 ) AThot H,0 =- ΔΙ cool H2O °C 87.86 )ATrot Hz0 = (229.702) ATe сool Hz0 AThot H,0 = (2.614)ATcool H20 Tf - 52.7°C = 2.614T; – 31.5°C 2.614T; : = 21.2°C Tf = = 8.11°C Heat and Enthalpy Solved Problems 2. Use the information provided to determine AH°rxn for the following reaction 3 Fe203 (s) + CO (g) → 2 Fe304 (s) + CO2 (g) ΔΗ ? rxn ΔΗ' Fe203 (s) Fe304 (s) CO (g) CO2 (g) -824 kJ/mol -1118 kJ/mol -111 kJ/mol -394 kJ/mol Answer: kJ (-824- mol kJ + -111 mol) kJ 1118· mol kJ + -394. mol) kJ 577 mol
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