1. Two people are pushing a stalled car, as the figure indicates. The mass of the car is 1850 kg. One person applies a force of 275 N to the car, while the other applies a force of 395 N. Both forces act in the same direction. A third force of 560 N also acts on the car, but in a direction opposite to that in which the people are pushing. This force arises because of friction and the extent to which the pavement opposes the motion of the tires. Find the acceleration of the car. 275 N 275 N +x 560 N 395 N 395 N Opposing force = 560 N (a) (b) Free-body diagram of the car

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter5: The Laws Of Motion
Section: Chapter Questions
Problem 5.18P: A force F applied to an object of mass m1, produces an acceleration of 3.00 m/s2. The same force...
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Two people are pushing a stalled car, as the figure indicates. The mass of the car is 1850 kg. One person applies a force of 275 N to the car, while the other applies a force of 395 N. Both forces act in the same direction. A third force of 560 N also acts on the car, but in a direction opposite to that in which the people are pushing. This force arises because of friction and the extent to which the pavement opposes the motion of the tires. Find the acceleration of the car.

1. Two people are pushing a stalled car, as the figure indicates. The mass of the car
is 1850 kg. One person applies a force of 275 N to the car, while the other applies a
force of 395 N. Both forces act in the same direction. A third force of 560 N also
acts on the car, but in a direction opposite to that in which the people are pushing.
This force arises because of friction and the extent to which the pavement opposes
the motion of the tires. Find the acceleration of the car.
275 N
275 N
+x
560 N
395 N
395 N
Opposing force = 560 N
(a)
(b) Free-body diagram of the car
Transcribed Image Text:1. Two people are pushing a stalled car, as the figure indicates. The mass of the car is 1850 kg. One person applies a force of 275 N to the car, while the other applies a force of 395 N. Both forces act in the same direction. A third force of 560 N also acts on the car, but in a direction opposite to that in which the people are pushing. This force arises because of friction and the extent to which the pavement opposes the motion of the tires. Find the acceleration of the car. 275 N 275 N +x 560 N 395 N 395 N Opposing force = 560 N (a) (b) Free-body diagram of the car
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