1. You have 150.0 mL of a 0.517 M solution of Ce(NO₃)₄. a. You have 150.0 mL of a 0.517 M solution of Ce(NO₃)₄. What mass (in grams) of Ce(NO₃)₄ would be required to make the solution? ____g b. You have 150.0 mL of a 0.517 M solution of Ce(NO₃)₄. What is the concentration of the nitrate ions in the solution? ____M c. You have 150.0 mL of a 0.517 M solution of Ce(NO₃)₄. If the original solution was diluted to 350.0 mL, what would be the new concentration of the Ce(NO₃)₄ in the solution? ____M

Introductory Chemistry: A Foundation
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1. You have 150.0 mL of a 0.517 M solution of Ce(NO₃)₄.

a. You have 150.0 mL of a 0.517 M solution of Ce(NO₃)₄. What mass (in grams) of Ce(NO₃)₄ would be required to make the solution?

____g
b. You have 150.0 mL of a 0.517 M solution of Ce(NO₃)₄. What is the concentration of the nitrate ions in the solution?
____M
c. You have 150.0 mL of a 0.517 M solution of Ce(NO₃)₄. If the original solution was diluted to 350.0 mL, what would be the new concentration of the Ce(NO₃)₄ in the solution?
____M
 
2. The synthesis of maleic acid anhydride (C₄H₂O₃) can be accomplished by reacting benzene (C₆H₆) and oxygen gas in the following chemical reaction: 2 C₆H₆(l) + 9 O₂(g) → 2 C₄H₂O₃(s) + 4 CO₂(g) + 4 H₂O(g)
a. What is the mass in grams of oxygen gas that is required to produce 53.9 grams of maleic acid anhydride?
_____g
b. What is the mass in grams of carbon dioxide that is produced from 67.6 grams of benzene?
c. What is the mass in grams of benzene that is required to produce 127.1 grams of maleic acid anhydride assuming the reaction has a 72.6% yield?
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