   Chapter 4.5, Problem 4.7CYU

Chapter
Section
Textbook Problem

An experiment calls for you to use 250. mL of 1.00 M NaOH, but you are given a large bottle of 2.00 M NaOH. Describe how to make the desired volume of 1.00 M NaOH.

Interpretation Introduction

Interpretation:

The making of desired volume of 1.00MofNaOH in a large bottle of 2.00MNaOH solution has to be described.

Concept Introduction:

• Concentration of solutions can be expressed in various terms; molarity is one such concentration expressing term.
• Molarity (M) of a solution is the number of gram moles of a solute present in one liter of the solution.

Molarity=MassperlitreMolecular mass

• A solution containing one gram mole or 0.1 gram of solute per litre of solution is called molar solution.
• Concentrationofsubstance=Amountof substancevolumeofthesubstance
• Amountof substance=Concentrationofsubstance×volumeofthesubstance
• V1×M1=V2×M2  where V1andV2 are the initial and final volume of the solution  M1andM2 are the initial and final molar concentration of the solution
Explanation

Measure accurately 125mL of 2.00MNaOH into a 250mL volumetric flask and add water to give a total volume of 250mL to make 1.00MofNaOH in a large bottle of 2.00MNaOH solution.

The initial volume of the solution to make 1.00MofNaOH in a large bottle of 2.00MNaOH solution can be determined by using the equation,

V1×M1=V2×M2

Thus,

(2

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