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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

An experiment calls for you to use 250. mL of 1.00 M NaOH, but you are given a large bottle of 2.00 M NaOH. Describe how to make the desired volume of 1.00 M NaOH.

Interpretation Introduction

Interpretation:

The making of desired volume of 1.00MofNaOH in a large bottle of 2.00MNaOH solution has to be described.

Concept Introduction:

  • Concentration of solutions can be expressed in various terms; molarity is one such concentration expressing term.
  • Molarity (M) of a solution is the number of gram moles of a solute present in one liter of the solution.

     Molarity=MassperlitreMolecular mass

  • A solution containing one gram mole or 0.1 gram of solute per litre of solution is called molar solution.
  • Concentrationofsubstance=Amountof substancevolumeofthesubstance
  • Amountof substance=Concentrationofsubstance×volumeofthesubstance
  • V1×M1=V2×M2  where V1andV2 are the initial and final volume of the solution  M1andM2 are the initial and final molar concentration of the solution
Explanation

Measure accurately 125mL of 2.00MNaOH into a 250mL volumetric flask and add water to give a total volume of 250mL to make 1.00MofNaOH in a large bottle of 2.00MNaOH solution.

The initial volume of the solution to make 1.00MofNaOH in a large bottle of 2.00MNaOH solution can be determined by using the equation,

  V1×M1=V2×M2

Thus,

  (2

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