What volume (mL) of 12 M HCl was required to react with the Mg? The data I have for you is this: Mg+2HCl-->MgCl2+H2 is the chemical equation. The mass of magnesium is 0.0273 grams and the moles is 0.001123 The moles of HCl that were consumed in the reaction was 0.002246 moles With this data, I need to know how we can get the volume (mL) of 12 M HCl was required to react with the Mg?
What volume (mL) of 12 M HCl was required to react with the Mg? The data I have for you is this: Mg+2HCl-->MgCl2+H2 is the chemical equation. The mass of magnesium is 0.0273 grams and the moles is 0.001123 The moles of HCl that were consumed in the reaction was 0.002246 moles With this data, I need to know how we can get the volume (mL) of 12 M HCl was required to react with the Mg?
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter4: Reactions In Aqueous Solution
Section: Chapter Questions
Problem 62QAP: Ten mL of concentrated H3PO4 (91.7% by mass, d=1.69g/mL) was accidentally poured into a beaker...
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What volume (mL) of 12 M HCl was required to react with the Mg?
The data I have for you is this:
Mg+2HCl-->MgCl2+H2 is the chemical equation.
The mass of magnesium is 0.0273 grams and the moles is 0.001123
The moles of HCl that were consumed in the reaction was 0.002246 moles
With this data, I need to know how we can get the volume (mL) of 12 M HCl was required to react with the Mg?
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