# 1.18 A mixture of argon and mercury vapor used in blueadvertising signs emits light of wavelength 470 nm. Calculate theenergy change resulting from the emission of 1.00 mol of photonsat this wavelength

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Step 1

The energy ‘E’ which is present in a photon is used to represent the smallest possible ‘packet’ of energy in the electromagnetic wave is directly proportional to the frequency of the wave. Planck’s equation is given as follows:

Step 2

The wavelength is given to be 470 nm =470×10-9 m= 47×10-8 m.

The speed of the light is 3×108 m/s

Planck’s constant = 6.626×10-34 m2kg/s

Substituting all the values in the Planck’s equation as follows:

Step 3

This is the energy of one photon. The energy of one mol of photon can be calcula...

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