1.44 grams of a sample of marble (impure calcium carbonate) dissolved in 40 ml of 1.0 normality (N) of hydrochloric acid, then add an amount of distilled water to the resulting solution, and its volume became 100 ml, it was found that 25 ml of this resulting solution (mixture) needs 19 ml of 0.2 normality (N) NaOH solution. Calculate the normality (mole/L) of the mixture solution and then calculate the percentage of pure calcium carbonate in this sample. If you know that the molecular weight of pure calcium carbonate
1.44 grams of a sample of marble (impure calcium carbonate) dissolved in 40 ml of 1.0 normality (N) of hydrochloric acid, then add an amount of distilled water to the resulting solution, and its volume became 100 ml, it was found that 25 ml of this resulting solution (mixture) needs 19 ml of 0.2 normality (N) NaOH solution. Calculate the normality (mole/L) of the mixture solution and then calculate the percentage of pure calcium carbonate in this sample. If you know that the molecular weight of pure calcium carbonate
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter1: Matter And Measurements
Section: Chapter Questions
Problem 54QAP: Potassium sulfate has a solubility of 15 g/ 100 g water at 40C. A solution is prepared by adding...
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: 1.44 grams of a sample of marble (impure calcium carbonate) dissolved in 40 ml of 1.0 normality (N) of hydrochloric acid, then add an amount of distilled water to the resulting solution, and its volume became 100 ml, it was found that 25 ml of this resulting solution (mixture) needs 19 ml of 0.2 normality (N) NaOH solution. Calculate the normality (mole/L) of the mixture solution and then calculate the percentage of pure calcium carbonate in this sample. If you know that the molecular weight of pure calcium carbonate
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