Microbiologists use acid-alcohol when performing a cell stain of the pathogen Mycobacterium tuberculosis. A common recipe is to make 3%(wevon HCl in ethanol. HCI has a formula weight of 36.46 grams per mole. If the stock solution of HCl is 1 moles per 1000 mL, how many ml of HCI need to be added to achieve a final volume of 500 mL of acid alcohol solution? Report your answer to two decimal places. Algebra can be used to solve this problem! In this context, the percentages act as concentrations. Therefore, it is possible to use m,v; = m,v2 and use the percentages as the concentration values. We can solve for m, by converting the molarity of HCI into a percentage using its formula weight. 36.46 g HCI m, Mol HCI m = x 100 = %HCI mol HCI 1000 mL Then substitute this value of m, into the equation m1v1 = m2V2 and solve for v, m2V2 (3%) (v2) V, = 36.46 g HCI 1 mol HCI m, Mol HCI (100) 1000 mL
Microbiologists use acid-alcohol when performing a cell stain of the pathogen Mycobacterium tuberculosis. A common recipe is to make 3%(wevon HCl in ethanol. HCI has a formula weight of 36.46 grams per mole. If the stock solution of HCl is 1 moles per 1000 mL, how many ml of HCI need to be added to achieve a final volume of 500 mL of acid alcohol solution? Report your answer to two decimal places. Algebra can be used to solve this problem! In this context, the percentages act as concentrations. Therefore, it is possible to use m,v; = m,v2 and use the percentages as the concentration values. We can solve for m, by converting the molarity of HCI into a percentage using its formula weight. 36.46 g HCI m, Mol HCI m = x 100 = %HCI mol HCI 1000 mL Then substitute this value of m, into the equation m1v1 = m2V2 and solve for v, m2V2 (3%) (v2) V, = 36.46 g HCI 1 mol HCI m, Mol HCI (100) 1000 mL
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter11: Solutions
Section: Chapter Questions
Problem 65AP
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