Microbiologists use acid-alcohol when performing a cell stain of the pathogen Mycobacterium tuberculosis. A common recipe is to make 3%(wevon HCl in ethanol. HCI has a formula weight of 36.46 grams per mole. If the stock solution of HCl is 1 moles per 1000 mL, how many ml of HCI need to be added to achieve a final volume of 500 mL of acid alcohol solution? Report your answer to two decimal places. Algebra can be used to solve this problem! In this context, the percentages act as concentrations. Therefore, it is possible to use m,v; = m,v2 and use the percentages as the concentration values. We can solve for m, by converting the molarity of HCI into a percentage using its formula weight. 36.46 g HCI m, Mol HCI m = x 100 = %HCI mol HCI 1000 mL Then substitute this value of m, into the equation m1v1 = m2V2 and solve for v, m2V2 (3%) (v2) V, = 36.46 g HCI 1 mol HCI m, Mol HCI (100) 1000 mL

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter11: Solutions
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QUESTION 4
Microbiologists use acid-alcohol when performing a cell stain of the pathogen Mycobacterium tuberculosis.
A common recipe is to make 3%(wevo) HCI in ethanol. HCI has a formula weight of 36.46 grams per mole. If the stock solution
of HCl is 1 moles per 1000 mL, how many mL of HCI need to be added to achieve a final volume of 500 mL of acid alcohol
solution? Report your answer to two decimal places.
Algebra can be used to solve this problem!
In this context, the percentages act as concentrations. Therefore, it is possible to use m;v, = m,v2 and use the percentages as the
concentration values. We can solve for m, by converting the molarity of HCI into a percentage using its formula weight.
36.46 g HCI
m, Mol HCI
m1 =
x 100 = %HCI
mol HCI
1000 mL
Then substitute this value of m, into the equation
m1v1 = m2V2
and solve for v,
m2V2
(3%) (v2)
V1 =
36.46 g HCI Y m1 Mol HCI
1 mol HCI
(100)
1000 mL
Solve for v, in a single step using Excel to avoid causing rounding errorl
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Transcribed Image Text:QUESTION 4 Microbiologists use acid-alcohol when performing a cell stain of the pathogen Mycobacterium tuberculosis. A common recipe is to make 3%(wevo) HCI in ethanol. HCI has a formula weight of 36.46 grams per mole. If the stock solution of HCl is 1 moles per 1000 mL, how many mL of HCI need to be added to achieve a final volume of 500 mL of acid alcohol solution? Report your answer to two decimal places. Algebra can be used to solve this problem! In this context, the percentages act as concentrations. Therefore, it is possible to use m;v, = m,v2 and use the percentages as the concentration values. We can solve for m, by converting the molarity of HCI into a percentage using its formula weight. 36.46 g HCI m, Mol HCI m1 = x 100 = %HCI mol HCI 1000 mL Then substitute this value of m, into the equation m1v1 = m2V2 and solve for v, m2V2 (3%) (v2) V1 = 36.46 g HCI Y m1 Mol HCI 1 mol HCI (100) 1000 mL Solve for v, in a single step using Excel to avoid causing rounding errorl Save All Answers Click Save and Submit to save and submit. Click Save All Answers to save all answers. O Type here to search hp
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