(10) You have 4 powdered samples, A, B, C, & D. One sample contains fullerenes, C16 to C70. Another is nano diamond. Another one is a mixture of C60 and carbon nanotubes. The 4th is a mixture of graphite & graphene. Indicate the analytical methods you would use to identify and distinguish the samples from each other.
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- Consider the titration illustrated in Figure 8.] Anhydrous sodium carbonate (Na₂CO₃) is a primary standard. When 0.364 grams of the substance is placed in a conical flask, then 20.00 cm³ of sulphuric acid (H₂SO₄) solution is required to reach the end point of the titration. What is the concentration in mol·dm⁻³ of the sulphuric acid solution? [Give the answer to 3 decimal places. Do not type in the unit. Use a decimal point.] *19 g of unknown organic sample was dissolve in 640 mL of Dicloromethane (DCM). The boiling point of benzene was increased by 3.78oC. Determine the molecular weight of the unknown sample? Kb of DCM = 2.42oC/m Bb of benzene = 39.6 oC density of benzene = 1.33 g/mL at 25 °C Round your answer to the nearest whole number, no units required.Mass solute needed to prepare 0.500L of 0.2 M NaCO3 from a solid NaCO3 with a purity of 92.0wt%
- 1. What is the MW of the analyte?2. What is the meq of the analyte?3. What is the weight (in grams) of the analyte?4. What will be the percentage purity of the sample if 43mL of the titrant was consumed?5. Did the sample conform to the USP requirement? Yes or No?When drinking water is disinfected with chlorine, an undesired byproduct, chloroform (CHCl3), may form. Suppose a 70-kg person drinks 2 L of water every day for 70 years with a chloroform concentration of 0.08 mg/L (the drinking water standard). Potency factor for chloroform = 6.1 x 10-3 (mg/kg-day)-1 The upper-bound cancer risk for this individual. a. 0.545 b. 5.45x10-6 c. 5.45x10-4 d. 5.45x10-10 e. 14x10-6 If a city with 300,000 people in it also drinks the same amount water described in the above question, how many extra cancers per year would be expected? Assume the standard 70-year lifetime. a. 0.163 b. 1.63x10-4 c. 1.63x10-3 d. 1.63x10-6 e. 6x10-2Beaker 0.00200 M Fe(NO3)3, mL 0.00200 M NaSCN, mL total volume, mL 1 3.000 2.000 10.00 2 3.000 3.000 10.00 3 3.000 4.000 10.00 4 3.000 5.000 10.00 5 (blank) 3.000 0.000 10.00 In Solutions 1-4 you are adding successively larger volumes of 0.00200M SCN- to the Fe3+ solution and diluting to 10.00 ml. Calculate the final diluted molarity of SCN- in solution #1 Your answer should have 3 sig figs =