10. MM and NN are amines with molecular formula, C3H9N. Reaction of MM with sodium nitrite and HCl releases nitrogen gas and produces a mixture of XX and YY, while NN produces yellowish oily compound ZZ when reacts with the same reagent. Gives the structures of MM, NN, XX, YY and ZZ. Outline a synthesis of MM from a suitable alkene.

10. MM and NN are amines with molecular formula, C3H9N. Reaction of MM with sodium nitrite and HCl releases nitrogen gas and produces a mixture of XX and YY, while NN produces yellowish oily compound ZZ when reacts with the same reagent. Gives the structures of MM, NN, XX, YY and ZZ. Outline a synthesis of MM from a suitable alkene.

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter21: Benzene And The Concept Of Aromaticity

Section: Chapter Questions

Problem 21.55P

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Describe the ozonolysis of alkenes one mole of a hydrocarbon(A) reacts with one mole of beomine giving a dibromo compound C5H10Br2.Substance A on treatment with cold dilute kMnO4 solution forms a compound C5C12O2(C5H12O2) on ozonolysis A,gives equimolar quantities of propanone and ethanol.Deduce the structure of substance A.
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1. Compound A, C9H12, absorbs 3 equivalents of H2 on catalytic hydrogenation over palladium catalyst to give B, C9H18. On the treatment with acidic KMnO4, compound A gives among other things, a ketone that was identified as cyclohexanone. On reaction with NaNH2 in NH3, followed by addition of iodomethane, compound A gives a new hydrocarbon C, C10H14. What are the structures of A , B and C?
Compound A has the molecular formula C14H25Br and was obtained by reaction of sodium acetylide (HC≡CNa) )with 1,12-dibromododecane. On treatment of compound A with sodium amide, it was converted to compound B (C14H24). Ozonolysis of compound B gave the diacid HO2C(CH2)12CO2H. Catalytic hydrogenation of compound B over Lindlar palladium gave compound C (C14H26), while hydrogenation over platinum gave compound D (C14H28). Sodium-ammonia reduction of compound B gave compound E (C14H26). Both C and E yielded O═CH(CH2)12CH═O on ozonolysis. Assign structures to compound A through E so as to be consistent with the observed transformations.
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