10. When 2.74 g of phosphorous is dissolved in 100.0 mL of carbon disulfide, CS2(), the boiling point is 46.71 °C. Given that the boiling point of pure carbon disulfide is 46.30 °C, that its density is 1.261 g mL-, and that its boiling-point elevation constant is K, = 2.34 K me, determine the molecular formula of phosphorous.

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10. When 2.74 g of phosphorous is dissolved in 100.0 mL of carbon disulfide, CS2(), the
boiling point is 46.71 °C. Given that the boiling point of pure carbon disulfide is 46.30 °C,
that its density is 1.261 g mL-1, and that its boiling-point elevation constant is Ko = 2.34 K
me1, determine the molecular formula of phosphorous.
Transcribed Image Text:10. When 2.74 g of phosphorous is dissolved in 100.0 mL of carbon disulfide, CS2(), the boiling point is 46.71 °C. Given that the boiling point of pure carbon disulfide is 46.30 °C, that its density is 1.261 g mL-1, and that its boiling-point elevation constant is Ko = 2.34 K me1, determine the molecular formula of phosphorous.
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