12-15 (a) HC \ H3C c=c CH3 CH3 1660 cm-¹ and 3000- 3100 cm-1 Н Н c=c CH3 CH(CH3)2 1660 cm-1

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter28: High-performance Liquid Chromatography
Section: Chapter Questions
Problem 28.14QAP
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This is referring to infrared spectroscopy. Why does the first double bond have a weak/non-existent peak while the second double bond has a moderate intensity peak?

12-15
(a)
H3C
H₂C
<=C
CH3
CH3
1660 cm-1
weak or non-existent
and
3000-
3100 cm-¹
310
H
H
c=c
CH3
CH(CH3)2
1660 cm-1
moderate intensity
Transcribed Image Text:12-15 (a) H3C H₂C <=C CH3 CH3 1660 cm-1 weak or non-existent and 3000- 3100 cm-¹ 310 H H c=c CH3 CH(CH3)2 1660 cm-1 moderate intensity
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