12. Compare the surface activity of propionic and butyric acids in aqueous solutions in this concentration range: C, mol/L. a, mN/mol Propionic acid Butyric acid 0.0312 69.5 65.8 0.0625 Is the Traube's Rule complied? 67.7 60.4
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- Sketch a plot of the fraction of species, f, vs pH for Tyr. Show your calculations for several points on the plot. You want to calculate the fraction of the species for more than 3 of the points. pKa’s for Tyr is 2.24, 9.04, and 10.10.Calculate the alkaline strength of pearl ash (impure potassium carbonate) in terms of percent K2O from the following data: Sample = 0.3500 g; HCl used = 48.03 mL; NaOH used for back titration = 2.02 mL; 1.000 mL HCl = 0.005300 g Na2CO3; 1.000 mL NaOH = 0.02192 g KHC2O4.H2O. (Note: Use the least significant digits in your answer.)A 370.00 mL solution of 0.00185 M A3B4 is added to a 390.00 mL solution of 0.00100 M C3D4. What is pQsp for A3D4?
- Calculate the concentration of A when chemical AB is dissolved in pure water. Ksp = 0.00001331 AB2(s) ⇌ A2+(aq) + 2B¯(aq) Enter answer to 3 sig figs using exponential format.Calculate the alkaline strength of pearl ash (impure potassium carbonate) in terms of percent K2O from the following data: Sample = 0.3500 g; HCl used = 48.03 mL; NaOH used for back titration = 2.02 mL; 1.000 mL HCl = 0.005300 g Na2CO3; 1.000 mL NaOH = 0.02192 g KHC2O4.H2O.Which of the following statements is advantageous? A). The main differences between potentiometric and conductometric titrations are that potentiometric titrations exemplify the analyte sample-by-sample while conductometric titrations show the potential of the analyte B). A conductivity is analyl from the people of the charge. C.) Conductivity increases rapidly as close as equivalence, as a strong acid and a strong base will decrease D). The conductor remains constant according to the viscosity of the pixel, the decomposer and its size, which consists of design modelling.
- A 200.00 mL solution of 0.00105 M AB4 is added to a 270.00 mL solution of 0.00245 M CD5. What is pQsp for AD4? pQsp = -log(Qsp)The salt K2HPO4 (potassium hydrogen phosphate) is a strong electrolyte but not a strong acid or base. Consider an F = 0.010 M solution of K2HPO4. a) Add the acid/base behavior of hydrogen phosphate by writing a “sequential dissociation scheme” for phosphoric acid (H3PO4). Then write mass balance equations for total phosphate and total potassium and give their numerical values. b) Write the charge balance equation for this solution. How may total species are there? [Count species in the charge balance equation and add any neutrals.] How many additional equations are needed for systematic treatment of equilibrium? Name them (give their usual symbols) c) Consider the KHPO4−(aq) ion pair. This is a new species, so what additional equation would you need? Tell how you would alter each charge or mass balance equation (if necessary) to include this species.The Henderson-Hasselbalch equation: a. relates the pH of a solution to the pKa and the concentration of acid and salt. b. allows the graphical determination of the molecular weight of a weak acid from its pH alone. c. is equally useful with solutions of acetic acid and of hydrochloric acid. d. employs the same value for pKa for all weak acids.
- 4. The molar absorptivities of the indicator weak acid HIn (K_{a} = 1.42 * 10 ^ - 5) and its conjugate base In at 570 were determined as epsilon(HIn) = 7120 and ε(In) = 961. The optical length b = 1.00 cm. (a) What is the absorbance of an unbuffered indicator solution having total indicator concentration 8.0 * 10 ^ - 5 (b) What is the absorbance of a buffered indicator solution having total indicator concentration 8.0 * 10 ^ - 5 and pH = 6.5 .Calculate the alkaline strength of pearl ash ( impure potassium carbonate) in terms of percent K2O from the following data: Sample=0.3500 g; HCl used=48.03 m; NaOH used for back titration=2.02 mL; 1.000 mL HCl = 0.005300 g Na2CO3; 1.000 mL NaOH = 0.02192 g KHC2O4·H2OYou have performed an iodimetric titration using a commercial vitamin C tablet. Based on the following information below, calculate the %(w/w) of vitamin C(MM=176.16 g/mol) in the tablet: Mass of tablet dissolved in 250.0 mL: 5.422 g Aliquot volume of sample titrated: 25.00 mL Concentration of KIO3: 0.023 M Final burrette volume: 41.31 mL Initial burrette volume: 8.89 mL Blank volume: 0.14 mL