14. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25oC, diamond, changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Using equations from the numbered list below, determine delta H for C(diamond) -> C(graphite) (1) C(diamond) + O2(g) -> CO2(g) ΔH = -395.4 kJ (2) 2CO2(g) -> 2CO(g) + O2(g) ΔH = 566.0 kJ (3) C(graphite) + O2(g) -> CO2(g) ΔH = -393.5 kJ (4) 2CO(g) -> C(graphite) + CO2(g) ΔH = -172.5 kJ

Chemistry: Principles and Practice
3rd Edition
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.97QE: The enthalpy of combustion of liquid n-hexane, C6H14, is 4159.5 kJ/mol, and that of gaseous n-hexane...
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14. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25oC, diamond, changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Using equations from the numbered list below, determine delta H for

C(diamond) -> C(graphite)

(1) C(diamond) + O2(g) -> CO2(g) ΔH = -395.4 kJ

(2) 2CO2(g) -> 2CO(g) + O2(g) ΔH = 566.0 kJ

(3) C(graphite) + O2(g) -> CO2(g) ΔH = -393.5 kJ

(4) 2CO(g) -> C(graphite) + CO2(g) ΔH = -172.5 kJ

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