16.  What volume of water vapor gas would be produced from the combustion of 535.55 grams of propane (C3H8) with 2,665.06 grams of oxygen gas, under a pressure of 0.96 atm and a temperature of 350. degrees C? Given: C3H8(g) + 5 O2(g) ---> 3 CO2(g) + 4 H2O(g) (OR C3 H8 ("g") + 5 O2 ("g") right arrow 3 C O2 ("g") + 4 H2O ("g")

Introductory Chemistry: A Foundation
8th Edition
ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter13: Gases
Section: Chapter Questions
Problem 141AP: Consider the following unbalanced chemical equation: 6H12O6(s) + O2(g) -> CO,(g) + H2O(g) What...
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16. 

What volume of water vapor gas would be produced from the combustion of 535.55 grams of propane (C3H8) with 2,665.06 grams of oxygen gas, under a pressure of 0.96 atm and a temperature of 350. degrees C? Given:

C3H8(g) + 5 O2(g) ---> 3 CO2(g) + 4 H2O(g)

(OR CH("g") + 5 O("g") right arrow 3 C O("g") + 4 H2O ("g")

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