16.792 g of Ba(OH)2 (171.342 g.mol-1) is weighed out and carefully dissolved to make a 500.00cm3 solution. A 25.00 cm3 of this solution is pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solution is then reacted with a 0.753 M solution of HNO3. Ba(OH)2(aq) + 2HNO3(aq) → Ba(NO3)2(aq) + 2H2O(l) The moles of Ba(OH)2 transferred to the beaker is:
16.792 g of Ba(OH)2 (171.342 g.mol-1) is weighed out and carefully dissolved to make a 500.00cm3 solution. A 25.00 cm3 of this solution is pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solution is then reacted with a 0.753 M solution of HNO3. Ba(OH)2(aq) + 2HNO3(aq) → Ba(NO3)2(aq) + 2H2O(l) The moles of Ba(OH)2 transferred to the beaker is:
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter3: Mass Relations In Chemistry; Stoichiometry
Section: Chapter Questions
Problem 24QAP: Twenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What is the...
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16.792 g of Ba(OH)2 (171.342 g.mol-1) is weighed out and carefully dissolved to make a 500.00cm3 solution. A 25.00 cm3 of this solution is pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solution is then reacted with a 0.753 M solution of HNO3.
Ba(OH)2(aq) + 2HNO3(aq) → Ba(NO3)2(aq) + 2H2O(l)
The moles of Ba(OH)2 transferred to the beaker is:
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