The phosphorus in a 0.2091-g sample was precipitated as the slightly soluble (NH4)3PO4 • 12 MoO3. This precipitate was filtered, washed, and then redissolved in acid. Treatment of the resulting solution with an excess of Pb2+ resulted in the formation of 0.2922 g of PbMoO4. Express the results of this analysis in terms of percent P2O5.

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