17. A researcher was interested in comparing the salaries of female and male employees at a particular company.Independent simple random samples of 8 female employees and 15 male employees yielded the followingweekly salaries (in dollars).Femalel Male722 518495760562 904880 1150556520 805904500 4805201250 9701005750 6057431640660Use a 0.05 significance level to test the claim that the mean salary of female employees is less than the meansalary of male employees. Use the traditional method of hypothesis testing.(Note: x1 = 8705.375, x2 = $817.067, s1 = $ 183.855, s2 = $330.146.)%3D%3D%3D%3D

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Asked Dec 12, 2019
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17. A researcher was interested in comparing the salaries of female and male employees at a particular company.
Independent simple random samples of 8 female employees and 15 male employees yielded the following
weekly salaries (in dollars).
Femalel Male
722 518
495
760
562 904
880 1150
556
520 805
904
500 480
520
1250 970
1005
750 605
743
1640
660
Use a 0.05 significance level to test the claim that the mean salary of female employees is less than the mean
salary of male employees. Use the traditional method of hypothesis testing.
(Note: x1 = 8705.375, x2 = $817.067, s1 = $ 183.855, s2 = $330.146.)
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17. A researcher was interested in comparing the salaries of female and male employees at a particular company. Independent simple random samples of 8 female employees and 15 male employees yielded the following weekly salaries (in dollars). Femalel Male 722 518 495 760 562 904 880 1150 556 520 805 904 500 480 520 1250 970 1005 750 605 743 1640 660 Use a 0.05 significance level to test the claim that the mean salary of female employees is less than the mean salary of male employees. Use the traditional method of hypothesis testing. (Note: x1 = 8705.375, x2 = $817.067, s1 = $ 183.855, s2 = $330.146.) %3D %3D %3D %3D

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Expert Answer

Step 1

Given data

1- denotes Female

2 – denotes Male

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X1 = 705.375, s1 183.855, n, = 8,x, = 817.067, s2 = 330.146, n2 = 15

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Step 2

Formulation of Hypothesis

Null Hypothesis : Mean salary of Female employee and male employee is same

H0: µ1 = µ2

Alternative Hypothesis: Mean salary of Female employee is less than the salary of mal...

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X1 – X2 t = 705.375 – 817.067 -0. 881 289.71 Sp. 15 Пу пz Pooled standard Deviation is calculated below |(n1 – 1) x sỉ + (n2 – 1) x s Sp (8 – 1) × 183.8552 + (15 – 1) x 330.146? 8+ 15 – 2 п + nz — 2 = 289. 71 T.INV (0.05,21)) to.o5,21 = -1.721(From Excel = T.INV(0.05,21)) to.05,n1+n2-2

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Statistics

Hypothesis Testing

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