Chapter10: Radioactivity And Nuclear Processes
Section: Chapter Questions
Problem 10.19E
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Question
11
Please answer in reagular notation
Expert Solution
Step 1
Given : Half life i.e t1/2 of reactant (radioactive isotope) = 176.5 hr.
And percent of reactant reacted 46.80 %.
Step 2
Since the decay reactions are first order reactions.
And we know that the relationship between the amount of reactant i.e [A] and time for a first order reaction is given by
=> ln
where [A] = final amount of reactant = (1 - 0.4680) [A]0 = 0.532 [A]0 (because 46.8 % is decaying)
[A]0 = initial amount of reactant = [A]0
t = time
K = Rate constant
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