18. If m/JKL = 48° and = 128°, calculate the measure of arc JL.. *Image not to scale. N J K measure of arc JL= 0 L M JK is a tangent to OQ. mJM = 0

Q: B 68 m/BCA= C Don't forget to put the degree symbol in each answer. m/ACD= D m/BAC = m/D= m/CAD=

A: To find out the following angles.

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Q: C. d. Determine whether each statement is true or false. Briefly explain why you chose your answer.…

A: We can answer the questions in the following steps.

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Q: 13) m/FCD=x+41, m/BCF=x+78, and m/BCD= 95° Find x.

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Q: square root of (94-55)

A: topic :- algebra

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Q: 5 432 1 -6 -5 -4 -3 2-1₁ -2 WN 3 -4 -5 D 12 2 3 4 5 6 7 8 -1) (2,-4) 16. (2,-5)

A: Question: Find the vertex, directrix, and the focus.

Q: Type the correct answer in the box. Round your answer to the nearest whole number. A manufacturer…

A: Topic:- Geometry

Q: 4. Now, let's assume that A, B, C, and D from above are each the resultant of 2 component vectors (x…

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Q: Name Practice Example 1 Refer to the number line. M 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 1.…

A: Topic:- application of geometry

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Q: Show illustration, define variables used and give a detailed solutions. 1. In the right triangle…

A: Given data:- In the right triangle ABC, AB=2BC=4ED∥ABL=AD+ED

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A: Triangle

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Q: LESSON 1.1 Practice A For use with pages 2-8 In Exercises 1-8, use the diagram. 1. Give two other…

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Q: 13

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Q: o run 2 km every day, calculate how many times you have to go around the track. 50.0 m 30.0 m

A: Solution :length of the track=50+15π+50+15π   radius=302=15m, perimeter of semicircle=πrlength of…

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A: We have given  height of the cone= 2 diameter h=2d As, diameter = 2 radius  d=2r So, h=2×2r h=4r…

Q: S=1 A=1 R= S Q R ht A U

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A: Please see the below picture for detailed solution.

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A: We can the answer the question in the below steps.

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Q: 75° 64° m/2= 2 (don't forget the degree symbol)

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Q: Use the information and diagram to complete the problem. Given: J is the midpoint of HL. AHIJ and…

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Q: Consider the following system. =x2-1 x₂ = x₁²x₁-₂ tl X a) Find the equlbrrum b) Plot Phase Portrail…

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Q: The two triangles are similar. Find the missing length. 12 16 O x = 24 Ox= 30 Ox=40 O x = 32 24 X 24…

A: The corresponding sides of similar triangles are in the same ratio.

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A: The translation is a transformation in coordinate geometry when an image is shifted along the x-axis…

Q: 1815851 LL LOK 173.4 328.51 What is the area in square feet? 182.981

A: Area of square = l*b area of right triangle = 1/2 *b*h area of triangle = sq rt[ s(s-a)(s-b)(s-c)]…

Q: 6. ALGEBRA If a supplement of an angle has a measure 78 less than the measure of the angle, what are…

A: 6. If a supplement of an angle has a measure 78 less than the measure of the angle.

Q: Discuss the difference between a coterminal angle and a reference angle. Coterminal angles are…

A: Option d is correct.

Q: . Use synthetic division to determine if x = 1 is a zero of P(x) = 2x4 + 5x² - 4. Show your work!

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Q: Use the following diagram to answer the discussion question. © 2019 StrongMind. Created using…

A: Solution

Q: Question 1 Write the equation of the line that is parallel to y=2x-5 and passes through (-2,-4)…

A: Please see the below picture for detailed solution.

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Q: Determine the equation of the wheels of Mr V's bicycle 30 28 26 24 22 20 18 16 14- 12 10 8. 6 4 2 4…

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Q: Find P.S. of (16x+5y) dx + (3x+y) dy = 0 If the curre to pass thru the point (1,-³)

A: The given equation is: (16x+5y)dx+(3x+y)dy=0⇒(16x+5y)dx=-(3x+y)dy⇒dydx=-16x+5y3x+y⇒dydx=-16+5yx3+yx

Q: 5. If x = 3 is a zero of P(x) = 3x³ + 3x² − 34x − 6, find all the other zeros. -

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Q: c. Calculate the thigh, shank and knee angles based on the XY coordinates of the hip, knee and ankle…

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Q: 1. Transform the general equation of the circle x² + y² + 8x - 2y - 8 =0 into its standard form and…

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Q: If possible, find the measure of angle X. 41° 74° OLX = 65° O Not enough informtion to solve OX= 41°…

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Q: 1. EXERCISES 3.1 Find the coordinates of the foci, and vertices, the endpoints of the major axis,…

A: Since you have posted multiple questions as per guidelines we can solve only one question at a time…