2-chloro-3methylbutane (show all confirmations) 1) looking down the C1-C2 bond 2) 1 staggered confimation looking down the C2-C3 bond 3) Label all and rank all from least to most stable.
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Q: Please help show and explain: All confirmations of 2-chloro-3methylbutane looking down the C1-C2…
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2-chloro-3methylbutane (show all confirmations)
1) looking down the C1-C2 bond
2) 1 staggered confimation looking down the C2-C3 bond
3) Label all and rank all from least to most stable.
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- Imagine that this worksheet has sucked you the plane of the page, and you are now facing the indicated bond of the drawn molecule. a. Draw the six main Newman projections for the indicated bond: three eclipsed, three staggered. b. Label which conformers are eclipsed ands taggered.c. Identify the most and least stable conformer, and explain your reasoning.Draw all possible structural (constitutional and cis-trans) isomers in bond-line presentations for the following compounds: A) C4H9Br (4 isomers) B) C3H7N (non cyclic compounds only) (at least 8 isomers including stereoisomers). C) C2H4F2 (not that many possibilities) D) C4H10O (7 isomers) E) C3H6O (compounds with single bonds only) (3 isomers) F) F2CCH2 (pay attention that the connectivity in this compound is already defined) G) C2H2Br2 (3 isomers including stereoisomers)Build a model of methylcyclohexane, and use the model to complete the following Newmanprojections of methylcyclohexane in the chair conformation: a. When the methyl group is in an axial or equatorial (circle one) position, the molecule is inits lowest potential energy conformation. b. Label one Newman projection above anti and the other gauche to describe the relationshipbetween the methyl group and C3 of the ring. c. In general, which is a lower PE conformation, anti or gauche? d. Explain how your answer to b and c provide an explanation for why it is more favorable fora large group to be in an equatorial than an axial position.
- How many secondary hydrogens are there in the following compound?Which of the following projections would the most stable? I believe that it would be the 6th because out of all 6 groups, the methyl groups are the furthest distance away from each other in the 6th. When they are in close proximity, the front and back methyl groups’ electron orbitals repel each other, which generates potential energy and makes the conformation unstable.Arrange the following molecules from largest to smallest dispersion: CH4 CH3CH2CH2CH2CH3 CH3C(CH3)2CH3 CH3CH(CH3)C(CH3)2CH2CH3 CH3H2CH3 CH3CH2(CH2)4CH2CH3
- Complete the Newman projection below to draw the most stable conformation of 3-methylpentane, looking down the C2-C3 bond. Identify each substituent using "H" for hydrogen and "Me" for methyl. a= b= c= d=Assign the stereochemical configuration (R or S) for each molecule. Show your work, indicating clearly which groups are assigned which priorities (#1 through #4) (e.g. by including the priority # directly adjacent to one of the atoms in that group).Draw a Newman projection, similar to Figure 3-25, down the C1¬C6 bond in the equatorial conformation of methylcyclohexane. Show that the equatorial methyl group is also anti to C5.
- Statement 1: The boiling point of compound2 is lower because of the number of bondingregions present Statement 2: Moreover the increased no. of sigmabonds result to more difficult distortion resulting to a stronger attractive force within the atoms prensent Which is true? Statement 1, 2, both, or nonetranslate the bond-line notation structure to the Newman projection by filling int the missing groups (A, B, C, D or E) on the lines in the Newman projection so they match the conformation given in the original structure. Circle if the conformation is a staggered or eclipsed.Then draw the most stable and least stable Newman projection conformation from the C4-C5 bond in the molecule above