2 H2(g) + O2(g) –→2 H2O(1)3. Calculate:a. the stoichiometric ratio of moles H2 to moles O, 2H/102=2,2:1b. the actual moles H2 to moles O2 when 3.50 mol H2 is mixed with 2.00 mol O2c. the limiting reactant (H2 or O2) for the mixture in part (b)d. the theoretical yield, in moles, of H2O for the mixture in part (b)

Given: The reaction is as follows: 2H2(g) + O2(g)----------->2H2O(l).

Answered: 2 H2(g) + O2(g) → 2 H2O(1) 3.…

EBK A SMALL SCALE APPROACH TO ORGANIC L

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Author:Lampman

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Chapter13: Isolation Of Eugenol From Clov

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