2-methyl-2-butanol + acetic acid -> www 3-methyl-2-butanol + acetic acid => 1-propanol + acetic acid –> www 1-Octanol + acetic acid 2-methyl - propanol + formic acid acetic acid –> ww wn
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- Oxidation of Butanol -1 in KMnO4/H+ will produce-------------. a.Butanoic Acid b.Butanal c.Pentanoic acid d.Butene -2Tunicates are marine animals that are called "sea squirts" because when they are taken out of water, they tend to contract and expel seawater. Lepadiformine is a cytotoxic agent (toxic to cells) isolated from a marine tunicate. During a recent synthesis of lepadiformine, the investigators observed the formation of an interesting by-product (3) while treating diol 1 with a reagent similar in function to PBr3 (J. Org. Chem. 2012, 77, 3390–3400):SHOW COMPLETE SOLUTIONS Q3. Which isolate has A260/280 ratio of above 2.0?
- Compound X is insoluble in cold KMnO4, Br2 in CCl4, and conc. H2SO4. Compound X is most likely: a. an alkane b. none of these c. an alkene d. an alcohol e. an alkyl halide Indicate which of the ff. statements regarding nucleophilicity is incorrect. F- is more nucleophilic, hence, more reactive towards methyl iodide than Cl-. Second row elements are more nucleophilic than first row elements of comparable basicity. The rate of SN2 reaction may be markedly affected by the nucleophilicity of the attacking atom. Nucleophilicity is the affinity of a nucleophile to an electrophilic carbon Which of the following alkynes can be deprotonated by NaNH2 in liquid NH3? 3-Methylhex-2-yne Pent-2-yne 3-Methylbutyne none of these Hex-3-yneOChem help with IUPAC names involving Ph and Bn The phenyl group (Ph-R, C6H5-R) can be formed by removing a hydrogen from benzene and attaching a substituent to where the hydrogen was removed. The benzyl group (abbv. Bn), similar to the phenyl group, is formed by manipulating the benzene ring. In the case of the benzyl group, it is formed by taking the phenyl group and adding a CH2 group to where the hydrogen was removed. Its molecular fragment can be written as C6H5CH2-R, PhCH2-R, or Bn-R. Please provide the IUPAC name for the following: (Ph)2CHC(CH3)2CC(CH2)3CH(Bn)CHOa. For this acid-base reaction: C⊖H3 + H3O+ −−→ CH4 + H2O, the conjugate acid of carboanion (C⊖H3) is _________________ b. Complete the equation: HC≡N + NaOH −−→ ___________+__________ c. Rank the acidity of these: NH3, HF, H2O, HCl, NaH Most acidic______>_______>_______>_______>_______least acidic d. The Ka of acetic acid (found in vinega) is 1.8×10-5. Then the pKa of formic acid is
- We react 2-propanone with 1º NaCN, H+, 2º LiAlH4 and 3º H3O+. Indicate the final product. Comment reactions.#B: Methyl acetate has methoxy, -OCH3 as the remaining of the alcohol part in the ester. Isopropyl acetate has isopropoxy, -OCH(CH3)2 as the remaining of the alcohol part in the ester. -OCH(CH3)2 is more electron donating than the methoxy, -OCH3 group due to the presence of two electron-donating -CH3 group in the former. Hence saponification reaction of Isopropyl acetate is much slower than methyl acetate. Hence the rate of saponification of methyl acetate, CH3CCO2CH3 is 50 times greater than that for isopropyl acetate.What is the strongest IMF in pure 2-octanone? I know it is a ketone and has some polarity due to this, but the carbon chain so long, I wonder if london dispersion forces are stronger?
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