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- Calculate the concentration of a solution of peptide AWSME, in mM if the absorbance at 280 nm for the solution is 0.6 absorbance units, and a 0.2-cm cuvette is used. For the extinction coefficient, take into account that e280(Trp) = 5690 M-1 cm-1 and e280(Tyr) = 1280 M-1 cm-1. Round your answer to two decimals.A Raman spectrum of undoped GaAs at room temperature is performed with a 514.5 nm laser. The spectrum of scattered light exhibits peaks at wavelengths of 507.1 nm and 591.6 nm due to interaction of the incident light with LO phonons. Calculate the LO phonon frequency and the ratio of the intensity of scattered light at 507.1 nm to that at 591.6 nm.Potassium dichromate (K2Cr2O7) and potassium permanganate (KMnO4) give overlapping UV-Vis absorption spectra in 1 M sulphuric acid. K2Cr2O7 shows an absorption maximum at 440 nm and KMnO4 shows the absorption maximum at 545 nm . An unknown sample solution containing a mixture of K2Cr2O7 and KMnO4 was analyzed using a 1-cm cell and the absorbance values at these two wavelengths were as follows: A440 = 0.515 and A545 = 0.835 The absorbance values for standard solutions of K2Cr2O7 (1.00 x 10-3 M) and KMnO4 (2.00 x 10-4 M) in 1 M sulphuric acid using the same 1 cm cell were as follows: Calculate the concentrations of K2Cr2O7 and KMnO4 in the unknown sample.
- An amino acid on the surface of a protein was labelled covalently with 1.5-I AEDANS and another was labelled covalently with FITC. The fluorescence quantum yield of 1.5-I AEDANS decreased by 10 per cent due to quenching by FITC. What is the distance between the amino acids? (Refer to Table 17G.3 for the appropriate value of R0.)A solution of Tryptophan has an absorbance at 280 nm of 0.54 in a 0.5 cm length cuvette. Given the absorbance coefficient of trp is 6.4 x 103 Lmol-1cm-1. What is the concentration of solution?Describe how to prepare adulterated palm oil samples before analysing it with Raman spectrometer. Also the describe the process how the Raman spectrometer will analyze the adulterated palm oil samples
- A student weighed out 0.150 g of protein powder and dissolved it in 100 mL of water (Solution 1). The student then diluted this solution by transferring 1 mL into a 25 mL flask and diluting with water (Solution 2). Finally, 1 mL of that solution was transferred to a test tube and combined with 4 mL Bradford reagent. The absorbance of the solution in the test tube was 0.144. Assuming that the best fit linear line of the standard curve was y=0.04144x+0.01521 (μgmL), calculate the percent protein by mass in the original protein powder.A student weighed out 0.150 g of protein powder and dissolved it in 100 mL of water (Solution 1). The student then diluted this solution by transferring 1 mL into a 25 mL flask and diluting with water (Solution 2). Finally, 1 mL of that solution was transferred to a test tube and combined with 4 mL Bradford reagent. The absorbance of the solution in the test tube was 0.187. Assuming that the best fit linear line of the standard curve was y = 0.04144 x + 0.01521 (μ g mL), calculate the percent protein by mass in the original protein powder.Using the absorbance of [FeSCN]+2 at the wavelength of maximum absorption which you obtained in part B, and the diameter of the tube, obtained in part A,calculate the molar extinction coefficient. given info: Concentration of Fe3+ stock solution, C1 = 0.001 M Volume of stock Fe3+ solution pipetted, V1 = 25mL Concentration of diluted stock solution, C2 = 0.0004 M Volume of Fe2+ solution and KSCN (upon mixing) = 10mL Weight of KSCN = 1g The reaction taking place is given as: The reaction taking place is given as: F e 3+ (aq) + SC N − (aq) ⇔Fe [SCN] 2+ (aq) the concentration of [FeSCN]2+ after the mixing of Fe3+ and SCN- is 2.5 x 10-3 M. Moles of [FeSCN]2+ = 2.5 x 10-5 moles Diameter:1.2cm The wavelength at which maximum absorption takes place is = 480 nm
- A water sample was run through the colorimetric procedure for the analysis of nitrate, giving 65.0% transmittance. A sample containing 1.00 ppm nitrate run through the exactly the same/identical procedure gave 24.6% transmittance. What was the concentration of nitrate in the first sample?A 20 ppm solution of a DNA molecule (unknown molecular weight) isolated from Escherichia coli was found to an absorbance of 0.80 in a 2-cm cell. Calculate the absorptivity of the molecule.There is a class of polyesters that have the general structure shown below. For example, in polyethylene terephthalate (PET) m =1. How would you expect the Tg ad Tm of these polymers to vary with m, given that the molecular weight of the chain is held constant? Give reasons for your answer. Also, assuming that you are now just considering one member of this class of polymers, say PET, how does the Tg vary with molecular weight, n.