2. (10+15=25 pts.) From a random sample of 10 students in a production management class, that covers a project assignment, the mean examination score was found to be 82.75 and the sample standard deviation was 3.24. For an independent random sample of 8 students in another consumer research class that does not cover a project assignment, the sample mean and standard deviation of exam scores were 75.62 and 7.27, respectively. It is assumed that the unknown population variances are not equal. In the light of these information, answer the following questions: a. Determine the number of degrees of freedom. b. Find the 95% confidence for the difference between the two population mean scores.

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2. (10+15=25 pts.) From a random sample of 10 students in a production management class,
that covers a project assignment, the mean examination score was found to be 82.75 and the
sample standard deviation was 3.24. For an independent random sample of 8 students in another
consumer research class that does not cover a project assignment, the sample mean and standard
deviation of exam scores were 75.62 and 7.27, respectively. It is assumed that the unknown
population variances are not equal. In the light of these information, answer the following
questions:
a. Determine the number of degrees of freedom.
b. Find the 95% confidence for the difference between the two population mean scores.
Transcribed Image Text:2. (10+15=25 pts.) From a random sample of 10 students in a production management class, that covers a project assignment, the mean examination score was found to be 82.75 and the sample standard deviation was 3.24. For an independent random sample of 8 students in another consumer research class that does not cover a project assignment, the sample mean and standard deviation of exam scores were 75.62 and 7.27, respectively. It is assumed that the unknown population variances are not equal. In the light of these information, answer the following questions: a. Determine the number of degrees of freedom. b. Find the 95% confidence for the difference between the two population mean scores.
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