2. In a Compton scattering event, an incident photon is scattered by a free electron initially at rest. h (where h is the Plank constant; m.c (i) If the scattered photon acquires a wavelength 1' = me is rest mass of electron; c is free-space light velocity), show that the scattered photon propagates in a direction perpendicular to that of the scattered electron. If the scattered electron propagates with kinetic energy 127.8 keV in a direction opposite to that of the scattered photon, as shown in Figure 2. Find the angle 0 , and therefore determine wavelengths of the incident and scattered photons, respectively. (ii)

Inquiry into Physics
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Chapter10: Atomic Physics
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In a Compton scattering event, an incident photon is scattered by a free electron initially at
rest.
(i) If the scattered photon acquires a wavelength
e
h
m c


(where h is the Plank constant;
me is rest mass of electron; c is free-space light velocity), show that the scattered
photon propagates in a direction perpendicular to that of the scattered electron.
(ii) If the scattered electron propagates with kinetic energy 127.8 keV in a direction
opposite to that of the scattered photon, as shown in Figure 2. Find the angle

, and
therefore determine wavelengths of the incident and scattered photons, respectively.

2. In a Compton scattering event, an incident photon is scattered by a free electron initially at
rest.
h
(where h is the Plank constant;
m.c
(i)
If the scattered photon acquires a wavelength 1' =
me is rest mass of electron; c is free-space light velocity), show that the scattered
photon propagates in a direction perpendicular to that of the scattered electron.
If the scattered electron propagates with kinetic energy 127.8 keV in a direction
opposite to that of the scattered photon, as shown in Figure 2. Find the angle 0 , and
therefore determine wavelengths of the incident and scattered photons, respectively.
(ii)
Transcribed Image Text:2. In a Compton scattering event, an incident photon is scattered by a free electron initially at rest. h (where h is the Plank constant; m.c (i) If the scattered photon acquires a wavelength 1' = me is rest mass of electron; c is free-space light velocity), show that the scattered photon propagates in a direction perpendicular to that of the scattered electron. If the scattered electron propagates with kinetic energy 127.8 keV in a direction opposite to that of the scattered photon, as shown in Figure 2. Find the angle 0 , and therefore determine wavelengths of the incident and scattered photons, respectively. (ii)
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