2. In Model 2, Example 1, solutions of sodium nitrate and potassium acetate are mixed together forming soluble products. If the solution were to be evaporated to dryness, name all of the compounds that might be found in the container.

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Chapter5: Stoichiometry
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Problem 97E
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Net Ionic Equations
Model 2: Net ionic reactions
When a soluble salt is placed in water, it separates into its ions. For example,
sodium chloride is soluble.
NaCl(s)
Nat (aq) + Cl(aq)
water
Example 1: Sodium nitrate reacts with potassium acetate in an aqueous
solution.
In double displacement (replacement) reactions, two ionic compounds react and
switch ions.
NaNO3 + KC₂H3O2 → KNO3 + NaC2H3O2
According to this "pencil and paper" reaction, potassium nitrate and sodium acetate
are produced. However, if this reaction is actually carried out in an aqueous
solution, nothing appears to happen.
If we investigate this system using the concept of a net ionic reaction we can see
why it appears that nothing happens. First, we write all of the compounds in the
equation, showing the ions that are formed when the reaction is carried out in
water.
Na+ (aq) + NO3(aq) + K+ (aq) + C₂H3O2 (aq) → K+ (aq) + NO3(aq) + Na+ (aq) + C2H3O2 (aq)
Next, we cross out any ions that are present on both the left (reactant) side and
right (product) side of the reaction.
N₂² (aq) + NO3(aq) + (aq) + C₂H5O2 (aq) →K(aq) + NO3(aq) +Na+ (aq) + C₂H5O2 (aq)
The ions we cross out, which are the same on both sides, are called spectator ions
(they are just "standing around watching", hence the term spectator).
Both of the compounds on the left hand side of the reaction (reactants) and the right
hand side of the reaction (products) are soluble. Therefore, no solid forms and no
reaction occurs. The ions are all simply floating around together in the solution.
Transcribed Image Text:Net Ionic Equations Model 2: Net ionic reactions When a soluble salt is placed in water, it separates into its ions. For example, sodium chloride is soluble. NaCl(s) Nat (aq) + Cl(aq) water Example 1: Sodium nitrate reacts with potassium acetate in an aqueous solution. In double displacement (replacement) reactions, two ionic compounds react and switch ions. NaNO3 + KC₂H3O2 → KNO3 + NaC2H3O2 According to this "pencil and paper" reaction, potassium nitrate and sodium acetate are produced. However, if this reaction is actually carried out in an aqueous solution, nothing appears to happen. If we investigate this system using the concept of a net ionic reaction we can see why it appears that nothing happens. First, we write all of the compounds in the equation, showing the ions that are formed when the reaction is carried out in water. Na+ (aq) + NO3(aq) + K+ (aq) + C₂H3O2 (aq) → K+ (aq) + NO3(aq) + Na+ (aq) + C2H3O2 (aq) Next, we cross out any ions that are present on both the left (reactant) side and right (product) side of the reaction. N₂² (aq) + NO3(aq) + (aq) + C₂H5O2 (aq) →K(aq) + NO3(aq) +Na+ (aq) + C₂H5O2 (aq) The ions we cross out, which are the same on both sides, are called spectator ions (they are just "standing around watching", hence the term spectator). Both of the compounds on the left hand side of the reaction (reactants) and the right hand side of the reaction (products) are soluble. Therefore, no solid forms and no reaction occurs. The ions are all simply floating around together in the solution.
2. In Model 2, Example 1, solutions of sodium nitrate and potassium acetate are
mixed together forming soluble products. If the solution were to be
evaporated to dryness, name all of the compounds that might be found in the
container.
Transcribed Image Text:2. In Model 2, Example 1, solutions of sodium nitrate and potassium acetate are mixed together forming soluble products. If the solution were to be evaporated to dryness, name all of the compounds that might be found in the container.
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