kg2. Oxygen at the rate of 1.36undergoes a reversible isobaric process during whichminKJ,V1= 0.5m3and T1= 204 °C. For both non-flow andminits entropy change is -1.465min Ksteady flow, change of kinetic and potential energy are both zero, compute: a) AU b)Δηc) Wnfd) Wsf

Given Data: The mass flow rate of oxygen is, m˙=1.36 kg/min. The change in entropy is, dS=-1.465…

2. Oxygen at the rate of 1.36 undergoes a reversible isobaric process during which min its entropy change is -1.465 KJ „V1= 0.5 m3 and T1= 204 °C. For both non-flow and min K min steady flow, change of kinetic and potential energy are both zero, compute: a) AU b) Ah c) Wnf d) Wsf

2. Oxygen at the rate of 1.36 undergoes a reversible isobaric process during which min its entropy change is -1.465 KJ „V1= 0.5 m3 and T1= 204 °C. For both non-flow and min K min steady flow, change of kinetic and potential energy are both zero, compute: a) AU b) Ah c) Wnf d) Wsf

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Center of Gravity and Centroid

The term center of gravity indicates the position or location of a point about which the whole weight of a body or system is supposed to be concentrated, which means the whole weight of the body or system works through this point. It is closely related to mass distribution. For all positions of the body, the center of gravity would be a single point.

Question

kg
2. Oxygen at the rate of 1.36
undergoes a reversible isobaric process during which
min
KJ
,V1= 0.5
m3
and T1= 204 °C. For both non-flow and
min
its entropy change is -1.465
min K
steady flow, change of kinetic and potential energy are both zero, compute: a) AU b)
Δη
c) Wnf
d) Wsf

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