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2. The reaction H2 (g) + 2 NO (g) → N20 (g) + H,O (g) is studied at a certain tempera- ture by determining the rate of reaction at reactant concentrations. The results are as follows. Concentration (M) Rate [NO] [H]] (M/s) (i) 0.25 0.10 0.126 (ii) 0.50 0.10 0.504 (ii) 0.50 0.20 1.03 The rate law is written as Rate k [NO]* [H2J". The exponents x and y represent the %3D order with respect to NO and H2, respectively. Calculate the value of x and y from the data provided.

2. The reaction H2 (g) + 2 NO (g) → N20 (g) + H,O (g) is studied at a certain tempera- ture by determining the rate of reaction at reactant concentrations. The results are as follows. Concentration (M) Rate [NO] [H]] (M/s) (i) 0.25 0.10 0.126 (ii) 0.50 0.10 0.504 (ii) 0.50 0.20 1.03 The rate law is written as Rate k [NO]* [H2J". The exponents x and y represent the %3D order with respect to NO and H2, respectively. Calculate the value of x and y from the data provided.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2. The reaction H2 (g) + 2 NO (g) → N20 (g) + H,O (g) is studied at a certain tempera- ture by determining the rate of reaction at reactant concentrations. The results are as follows. Concentration (M) Rate [NO] [H]] (M/s) (i) 0.25 0.10 0.126 (ii) 0.50 0.10 0.504 (ii) 0.50 0.20 1.03 The rate law is written as Rate k [NO]* [H2J". The exponents x and y represent the %3D order with respect to NO and H2, respectively. Calculate the value of x and y from the data provided.
Transcribed Image Text:2. The reaction H2 (g) + 2 NO (g) → N20 (g) + H,O (g) is studied at a certain tempera- ture by determining the rate of reaction at reactant concentrations. The results are as follows. Concentration (M) Rate [NO] [H]] (M/s) (i) 0.25 0.10 0.126 (ii) 0.50 0.10 0.504 (ii) 0.50 0.20 1.03 The rate law is written as Rate k [NO]* [H2J". The exponents x and y represent the %3D order with respect to NO and H2, respectively. Calculate the value of x and y from the data provided.
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