2.4e+05 2.2e+05 2.0E+05 1.8e+05 1.6e+05 1.4e+05- 1.2e+05 1.0e+05- 8.0E+04- 6.0E+04 4.0E+04- 2.0E+04- 0.0e+00 T 11 10 -8.933 1.00 -7.385 A 1.13 5.305 4.973 -4.831 4.594 3
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- Dd.36. With explanation please .....NH4+ {aq) + NO2(aq) -> N2(g) +2H2O{l} Data Initial [NH4+] Initial [NO2-] rate 1 0.0100 0.200 5.4 x10-7 2 0.0200 0.200 10.8x10-7 3 0.0400 0.200 21.5x10-7 4 0.200 0.0202 10.8x10-7 5 0.200 0.0404 21.6x10-7 6 0.200 0.0808 43.3x10-7 Find x,y,kIf the a and b loci are 16 mu apart in humans and an A B / a b woman marries an a b / a b man. What is the probability that their first child will be A b / a b? 0.08 0.16 0.32 0.84 0.64
- WATCH THIS TWO MINUTE VIDEO TO SOLVE https://www.youtube.com/watch?v=9Wxxv7kwXlA&list=PLE-217H0ao60Uzpzj-FNP_0ScVp5SZB7j&index=8 What is the theoretical yield of this experiment? 1.217g 49% 4.9g .0893gA group of students compiled the data shown in data table 1 below. What is the exact calculated order for I-(aq) to 2 decimal places? Exp. # [IO3-]0 (M) [I-]0 (M) [H+]0 (M) Time (s) 1 0.005 0.05 2 x 10-5 22.12 2 0.010 0.05 2 x 10-5 86.84 3 0.005 0.10 2 x 10-5 5.35 4 0.005 0.05 4 x 10-5 2.65 Question 5 options: 1.49 -2.49 -1.72 1.65 2.44 -1.97 -1.53 2.05 2.24 -2.36 -2.13 1.81Choices: A. SLOPE a. -13532 b. -2.0 x 10^-6 c. 2.0 x 10^-5 d. 0.163 B. Y-intercept a. 6.7 x 10^-3 b. 37.44 c. 9.0 × 10^6 d. 56.68 C. Collision.. a. 1.01 b. 9.0 x 10^6 c. 1.82 x 10^16 d. 4.13 x 10^24 D. Activation.. a. 1.13 x 10^5 b. 1.36 c. 1.66 x 10^-4 d. 1.66 × 10^7
- 6. The FINAL ANSWER to PROBLEM # 3 is:A. 3.7 X 102yearsB. 3.7 X 103yearsC. 3.7 X 104yearsD. 37.05 years E. 370.5 yearsF. 370 500 yearsYou are trying to come up with a drug to inhibit the activity of an enzyme thought to have a role in liver disease. In the laboratory the enzyme was shown to have a Km of 1.0 x 10-6 M and Vmax of 0.1 micromoles/min.mg measured at room temperature. You developed an uncompetitive inhibitor. In the presence of 5.0 x 10-5 M inhibitor, the apparent Vmax was determined to be 0.02 micromoles/min.mg. What is the Ki of the inhibitor?In aqueous solution, chlorine dioxide oxidizes iodide ion to iodine and chlorine dioxide is reduced to chlorite ion. 2ClO2 (aq) + 2 I- (aq) ----> 2ClO2- (aq) + I2 (aq) The concentration in molarity, of ClO2 was measured at various time points. The data was plotted and the plot of [1/[ClO2] versus time in seconds was most linear. The linear regression equation for the plot is y= 7.60x10-2 (t) + 2.353. What is the concentration of ClO2 at 2.00 minutes if the initial concentration of ClO4 ia 0.425 M? a.) 0.0872 M b.) 2.50 M c.) 11.5 M d.) 0.399 M
- In Part B, you used a similar procedure to that of Part A to determine the mass percent of CaCO3 in an antacid tablet. The commercially accepted range of CaCO3 in an antacid tablet is 25–35% by mass. Miranda obtained the data below from her Part B trial: TRIAL PRESSURE (torr) MASS OF TABLET (g) TEMPERATURE (°C) VOLUME CO2 RECOVERED (mL) 1 750.5 0.5702 21.3 69.6 2 750.5 0.5622 21.2 68.2 Miranda determined her average % Recovery of CO2 to be 65.0% from Part A. Based on her data collected from Part A, was the average percent mass of CaCO3 in her antacid tablet within the commercially accepted range? Yes, her mass percent does fall within the commercially accepted range. No, her mass percent does not fall within the commercially accepted range.You are in lab doing an experiment, so far this is your data: Pb(CH3COO)2 (aq) + H2S (aq) → PbS (s) + CH3COOH (aq) 10g Pb (CH3COO)2 + 3g H2S produce 11.56g of led sulfate + 1.44g S 18g Pb (CH3COO)2 + 1.56g H2S produce 11.56g of led sulfate + 8.00g S Based on this data. What type of reaction is it? How many grams of sulfur do you need to completely react 10.00g of Pb. Balanced equation.The percentage protein content of chicken breasts are determined 5 times and the following results obtained: 28.5, 30.1, 30.2, 30.0 en 30.2%. The first value (28.5%) appears anomalous. Should it be retained or rejected at a 90% confidence level? Show all equations.