23. How much energy can be obtained from the roasting of 44.97 g of solid zinc sulfide given the following thermochemical equations ZnS) + /,0219) → ZnO(e) + SO29) (1) ZnO(s) → Zn(s) + ½O2(g) (2) S(s) + O29) → SO29) (3) ZnS(s) → Zn(s) + S(s) AH°, = +350.5 kJ AH°, = -296.8 kJ AH° = +206.0 kJ Show your work: Identify the law:

Chemistry by OpenStax (2015-05-04)
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Chapter16: Thermodynamics
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Problem 33E: Use the standard free energy of formation data in Appendix G to determine the free energy change for...
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23. How much energy can be obtained from the roasting of 44.97 g of solid zinc sulfide given the following
thermochemical equations
ZnS) + 1,0219) → ZnOcs)
SO219)
+
(1) ZnO(s) → Zn(s) + ½O29)
(2) S(s) + O2(g) → SO29)
AH°, = +350.5 kJ
AH°, = -296.8 kJ
AH°, = +206.0 kJ
%3D
1
%3D
(3) ZnS(s) → Zn(s) + S(s)
Show your work:
Identify the law:
Transcribed Image Text:23. How much energy can be obtained from the roasting of 44.97 g of solid zinc sulfide given the following thermochemical equations ZnS) + 1,0219) → ZnOcs) SO219) + (1) ZnO(s) → Zn(s) + ½O29) (2) S(s) + O2(g) → SO29) AH°, = +350.5 kJ AH°, = -296.8 kJ AH°, = +206.0 kJ %3D 1 %3D (3) ZnS(s) → Zn(s) + S(s) Show your work: Identify the law:
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