250-g ball at the end of a string is revolving uniformly in a horizontal circle of radius 0.70 m. The ball mal revolutions per second. (a) What is its centripetal acceleration? (b) What force is to be exerted on the string Solution: Given: m=250 g = 0.25 kg; r = 0.70 m; w = 2.0 rps a) The given angular velocity is in revolutions per second, we need to convert it yet to radian measures: rev 2π καὶ rad 4(3.1416) nd w = 2 = 12.6 rad/sec 1 rev a. Therefore, a = w²r = ( -X sec The force on the string is F = ma. Fc= Note: 1 N = 1 kg-m/sec² = 4 )²( sec sec _m/s² N
Gravitational force
In nature, every object is attracted by every other object. This phenomenon is called gravity. The force associated with gravity is called gravitational force. The gravitational force is the weakest force that exists in nature. The gravitational force is always attractive.
Acceleration Due to Gravity
In fundamental physics, gravity or gravitational force is the universal attractive force acting between all the matters that exist or exhibit. It is the weakest known force. Therefore no internal changes in an object occurs due to this force. On the other hand, it has control over the trajectories of bodies in the solar system and in the universe due to its vast scope and universal action. The free fall of objects on Earth and the motions of celestial bodies, according to Newton, are both determined by the same force. It was Newton who put forward that the moon is held by a strong attractive force exerted by the Earth which makes it revolve in a straight line. He was sure that this force is similar to the downward force which Earth exerts on all the objects on it.
General Physics
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