29. An integrative rate law experiment shows that the plot of In [NO2] vs. time is a straight line (in Fig. 2) for the reaction: 6NO2 (g) → 3 O2 (g) + 6NO (g) 08 Time (min) [NO:] (M) 2.0000 0.0000 with the ivenlf 0.6 5.0000 10.000 15.000 1.5874 1.2599 0.4 1.0000 In [NO,] 20.000 0.79370 0.2 Part 1. The reaction is order. a) zero-th b) first c) second d) third e) none of the above -0.2 10 15 20 Part 2.The rate constant with correct units of the above reaction is time (min) Fig. 2 a) 0.0667 M' min! b) 0.0462 min c) 0.0826 M min d) 1.960 min e) none of the above

Chemistry for Engineering Students
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Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.48PAE: 11.48 The following data were collected for the decomposition of NT),-: Time, f (min) [N2Os] (mol...
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29. An integrative rate law experiment shows that the plot of In [NO2] vs. time is a straight line (in Fig. 2) for the reaction:
6NO2 (g) → 3 O2 (g) + 6NO (g)
0.8
Time (min)
crall retion
[NO2] (M)
2.0000
0.0000
the given half
tionNose
0.6
5.0000
1.5874
10.000
1.2599
0.4
15.000
1.0000
In [NO,]
20.000
0.79370
0.2
Part 1. The reaction is
order.
a) zero-th b) first c) second
d) third e) none of the above
-0.2
0.
5.
10
15
20
Part 2.The rate constant with correct units of the above reaction is
time (min)
Fig. 2
a) 0.0667 M-' min
b) 0.0462 min-!
c) 0.0826 M min!
d) 1.960 min
e) none of the above
Transcribed Image Text:29. An integrative rate law experiment shows that the plot of In [NO2] vs. time is a straight line (in Fig. 2) for the reaction: 6NO2 (g) → 3 O2 (g) + 6NO (g) 0.8 Time (min) crall retion [NO2] (M) 2.0000 0.0000 the given half tionNose 0.6 5.0000 1.5874 10.000 1.2599 0.4 15.000 1.0000 In [NO,] 20.000 0.79370 0.2 Part 1. The reaction is order. a) zero-th b) first c) second d) third e) none of the above -0.2 0. 5. 10 15 20 Part 2.The rate constant with correct units of the above reaction is time (min) Fig. 2 a) 0.0667 M-' min b) 0.0462 min-! c) 0.0826 M min! d) 1.960 min e) none of the above
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