The sulfur from 4.00g steel is evolved as dihydrogen sulfide gas and titrated with 1.60 mL of 0.0500N iodine solution. How many milliliters if iodine will be reduced by 40.00 mL of Na2S2O3 solution of which 1mL thiosulfate solution = 0.006354g Cu? H2S + 12 → S + 21- + 2H+ AsO33- + 2HCO3- + l2 → AsO43- + 21- + 2CO2 + H20 2Cu2+ + 41- → 2Cul + l2 103 + 61- + 6H+ → 312 + - 3H2O 4.0mL 2.0mL 80mL O 160mL

Fundamentals Of Analytical Chemistry
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Chapter31: Introduction To Analytical Separations
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Problem 31.21QAP
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The sulfur from 4.00g steel is evolved as dihydrogen sulfide gas and titrated
with 1.60 mL of 0.0500N iodine solution. How many milliliters if iodine will be
reduced by 40.00 mL of Na2S2O3 solution of which 1mL thiosulfate solution =
%3D
0.006354g Cu?
H2S + 12 → S + 21- + 2H+
AsO33- + 2HCO3 + l2 → AsO43- + 21- + 2CO2 + H2O
2Cu2+ + 41- → 2Cul + l2
103- + 61- + 6H+ → 312 + - 3H2O
4.0mL
2.0mL
80mL
160mL
Transcribed Image Text:The sulfur from 4.00g steel is evolved as dihydrogen sulfide gas and titrated with 1.60 mL of 0.0500N iodine solution. How many milliliters if iodine will be reduced by 40.00 mL of Na2S2O3 solution of which 1mL thiosulfate solution = %3D 0.006354g Cu? H2S + 12 → S + 21- + 2H+ AsO33- + 2HCO3 + l2 → AsO43- + 21- + 2CO2 + H2O 2Cu2+ + 41- → 2Cul + l2 103- + 61- + 6H+ → 312 + - 3H2O 4.0mL 2.0mL 80mL 160mL
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