2N₂O(g) → 2N,(g) + 0,(g) The rate law for the reaction represented above is experimentally determined to be rate kN₂O. Which of the following best explains why increasing the initial concentration of N₂O(g) ata constant temperature increases the reaction rate? A 0 @ Molecular collisions become more frequent There is a higher probability of effective molecular collisions. The tate constant for the reaction increases. D The reaction mechanism changes to one that has a lower activation energy

Chemistry: Principles and Practice
3rd Edition
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter13: Chemical Kinetics
Section: Chapter Questions
Problem 13.50QE
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Hh.195.

 

2N₂O(g) → 2N,(g) + 0(g)
The rate law for the reaction represented above is experimentally determined to be rate kN₂O). Which of the following best explains why increasing the initial concentration of N₂O(g) ata
constant temperature increases the reaction rate?
A
O
O
D
Molecular collisions become more frequent
There is a higher probability of effective molecular collisions.
The tate constant for the reaction increases.
The reaction mechanism changes to one that has a lower activation energy
Transcribed Image Text:2N₂O(g) → 2N,(g) + 0(g) The rate law for the reaction represented above is experimentally determined to be rate kN₂O). Which of the following best explains why increasing the initial concentration of N₂O(g) ata constant temperature increases the reaction rate? A O O D Molecular collisions become more frequent There is a higher probability of effective molecular collisions. The tate constant for the reaction increases. The reaction mechanism changes to one that has a lower activation energy
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