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3) Consider the balanced equation: 2 CH3OH (+3 02 (g) → 4 H₂O (g) + 2 CO2 (g) If you were to burn 20.5 grams of methanol, CH3OH, in 35.6 liters of oxygen gas, O2, at STP, how many grams of carbon dioxide, CO₂, would be formed? (Molar mass of CH3OH = 32.05 grams/mole, Molar mass of CO₂ = 44.01 gram/mole)

3) Consider the balanced equation: 2 CH3OH (+3 02 (g) → 4 H₂O (g) + 2 CO2 (g) If you were to burn 20.5 grams of methanol, CH3OH, in 35.6 liters of oxygen gas, O2, at STP, how many grams of carbon dioxide, CO₂, would be formed? (Molar mass of CH3OH = 32.05 grams/mole, Molar mass of CO₂ = 44.01 gram/mole)

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter10: Gases And Their Properties
Section: Chapter Questions
Problem 61GQ: Butyl mercaptan, C4H9SH, has a very bad odor and is among the compounds added to natural gas to help...
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Limiting Reactant Practice If you were to burn 20.5 grams of methanol, CH3OH, in 35.6 liters of oxygen gas, O2, at STP, how many grams of carbon dioxide, CO2, would be formed? (Molar mass of CH3OH = 32.05 grams/mole, Molar mass of CO2 = 44.01 gram/mole) 4) You performed
3) Consider the balanced equation: 2 CH3OH (+3 02 (g) → 4 H₂O (g) + 2 CO2 (g) If you were to burn 20.5 grams of methanol, CH3OH, in 35.6 liters of oxygen gas, O2, at STP, how many grams of carbon dioxide, CO₂, would be formed? (Molar mass of CH3OH = 32.05 grams/mole, Molar mass of CO₂ = 44.01 gram/mole)
Transcribed Image Text:3) Consider the balanced equation: 2 CH3OH (+3 02 (g) → 4 H₂O (g) + 2 CO2 (g) If you were to burn 20.5 grams of methanol, CH3OH, in 35.6 liters of oxygen gas, O2, at STP, how many grams of carbon dioxide, CO₂, would be formed? (Molar mass of CH3OH = 32.05 grams/mole, Molar mass of CO₂ = 44.01 gram/mole)
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