3. For a mole of a perfect monoatomic gas, the internal energy, U, can be expressed as a function of the pressure and volume as 3 U = U(P,V) = PV a) Calculate explicitly the line integral of dU along the closed path ABCD shown as a black trace in the P – V graph below. D C 3P1 2P1 P1 -> A V V1 2V1 3V1 4V1 5V1 6V1 Problem 3a-3c b) Compute the following line integrals between the points B and C in the figure above: 1. S, PdV, along the path, h, described by P = 3P;V/(V – 3V1), shown in red in the figure above. 2. S, PdV, along the path, s, shown in black in the figure above. Use these results to demonstrate that &W = -PdV is not an exact differential. S.
3. For a mole of a perfect monoatomic gas, the internal energy, U, can be expressed as a function of the pressure and volume as 3 U = U(P,V) = PV a) Calculate explicitly the line integral of dU along the closed path ABCD shown as a black trace in the P – V graph below. D C 3P1 2P1 P1 -> A V V1 2V1 3V1 4V1 5V1 6V1 Problem 3a-3c b) Compute the following line integrals between the points B and C in the figure above: 1. S, PdV, along the path, h, described by P = 3P;V/(V – 3V1), shown in red in the figure above. 2. S, PdV, along the path, s, shown in black in the figure above. Use these results to demonstrate that &W = -PdV is not an exact differential. S.
Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter4: Gibbs Energy And Chemical Potential
Section: Chapter Questions
Problem 4.42E: Use the ideal gas law to demonstrate the cyclic rule of partial derivatives.
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