3. Given: AH° -918.0 kJ AH° = 125.2 kJ Br₂(l) + 5F₂(g) ---> 2BrF5(¤) BrF3(€) + Br₂(€) ---> 3BrF(g) 2NaBr(s) + F2(g) ---> 2NaF(s) + Br₂(€) AH° = −316.0 kJ NaBr(s) + F₂(g) ---> NaF(s) + BrF(g) AH° = -216.6 kJ calculate AH° for the reaction: BrF3(l) + F₂(g) ---> BrF5(l) =

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