3. Ho: p= 0.78, p^= 0.81, Zcritical = Decision: 4. Ho: p = 0.28, p= 0.3, Zcritical Decision: n=50, n=50, Ha: p# 0.78 confidence level= 99% Zcomputed = confidence level = 95% Zcomputed = Ha: p = 0.28
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- A political candidate has asked his/her assistant to conduct a poll to determine the percentage of people in the community that supports him/her. If the candidate wants a 10% margin of error at a 95% confidence level, what size of sample is needed? Be sure to round accordingly.The candidate would need to survey people in the community in order to be within a 10% margin of error at a 95% confidence level.Suppose that we are interested in hypothesis testing and confidence intervals for a single proportion. Explain why it is possible for the conclusion of a hypothesis test done at significance level 0.05 to be different from the inference drawn from a 95% confidence interval that is constructed from the same data used to conduct the test.A hypothesis that was established to determine whether the strengths of two different materials are equal and tested at the 5% error level was rejected. If the same hypothesis is tested at the 94.9% confidence level, is it likely to be accepted? Please explain.
- Some analysts suggest that the average credit card debt for college students is $5,000, but university officials do not think that is true (i.e. the alternative hypothesis is H1: µ ≠ $5,000). If the 95% confidence interval estimating average credit debt among students is [$4,095, $5,025], what conclusion can be drawn? a. $5,000 is in the interval, so we fail to reject the null. b. $5,000 is not in the interval, so another sample is needed. c. $5,000 is not in the interval, so we reject the null. d. Since this was not based on a population, we cannot make a conclusion.In a recent study, researchers found that 31 out of 150 boys aged 7-13 were overweight or obese. On the basis of this study can we conclude that more than 15% of the boys aged 7-13 in the sampled population are overweight or obese? Use a 5% level of significance. Give each of the following to receive full credit: 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic; and 5) your conclusion including a comparison to alpha or the critical value. You MUSTshow your work to receive full credit. Partial credit is availableIn constructing a confidence interval from a manageable sample in order to estimate a population mean at a 0.10 level of significance, the null hypothesis formulated could not be rejected. Therefore, the company assumed that the value hypothesized is useful for its decision making. However, if the test had been conducted at a 0.05 level of significance, the same null hypothesis would have been rejected. Why would this be? What is involved in deciding the level of confidence and how does it relate to the sample size and the resources that the Company should dedicate to hypothesis testing?
- Suppose that you want to conduct a left-tailed hypothesis test at the 5% significance level. How must the critical value be chosen?A proponent of a new proposition on a ballot wants to know the population percentage of people who support the bill. Suppose a poll is taken, and 589 out of 1000 randomly selected people support the proposition. Should the proponent use a hypothesis test or a confidence interval to answer this question? Explain. If it is a hypothesis test, state the hypotheses and find the test statistic, p-value, and conclusion. Use a 5% significance level. If a confidence interval is appropriate, find the approximate 90% confidence interval. In both cases, assume that the necessary conditions have been met. Should the proponent use a hypothesis test or a confidence interval? (If both a hypothesis test and a confidence interval could be used, choose the simpler one.) A. The proponent should use a confidence interval because the proponent wants to know the proportion of the population who will vote for the proposition. A hypothesis test would be impossible. B. The proponent…1. The Malayo Colleges Mindanao recently conducted a study analyzing the privacy management habits of teen internet users. In a group of 154 teens, 108 reported having more than 100 followers on Twitter. Find the point estimate of a 90% confidence interval for the true proportion of teens who would report having more than 100 followers on Twitter.
- 2. The Vice-Chancellor of a university is concerned that illicit drug use on campus is higher than the 5% acceptable level. A random sample of 140 students revealed that 5 of them had used illicit drug during the last 12 months. Construct a 90% confidence interval to estimate the true proportion of students who use illicit drug. Should the Vice-Chancellor be concerned?Suppose researchers carry out a one-way ANOVA involving 4 groups. After finding statistically significant evidence of a difference in the group means, they decide to use the Bonferroni correction to come up with simultaneous confidence intervals for the pairwise differences, keeping the family-wise confidence level at least 85%. Help the researchers out here. Using the Bonferroni approach, what should the confidence level be for the individual intervals? Important: Enter your answer as a percentage confidence level, but without the percent sign. For example, if your answer is 98.627%, enter 98.627. (Give your response to at least 3 decimal places. Give only your numeric response, and not any extra characters or symbols.)4) Estimate the difference between the proportion of females and males that are very satisfied from the rooms.5) Estimate the difference between the proportion of females and males that are very satisfied from the rooms with 95% confidence.6) Test at 0.01 significance level if the proportion of females that are very satisfied from the rooms is same as that of males.