3. Rearrange the molecules from strongest IMFS to weakest. C,H0 C,H, CH C,H

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter14: Elimination
Section: Chapter Questions
Problem 29CTQ
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3. Rearrange the molecules from strongest IMFS to weakest.
CH0
C,H,
CH
C,H
...
notes
DELL
Transcribed Image Text:3. Rearrange the molecules from strongest IMFS to weakest. CH0 C,H, CH C,H ... notes DELL
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This question is answered by using the simple concept of intermolecular forces (IMF) of alkanes. In alkanes the strength of intermolecular forces increases with increase in the number of carbon atoms because molecular mass increases.

The correct order of IMF from strongest to weakest is given as follows,

 

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