3. The elastic portion of the stress-strain diagram for a titanium alloy used for medical implants shown. The specimen from which it was obtained has an original diameter of 10 mm and a gage length of 45 mm. If a tensile load of P = 300 kN is applied to the specimen. Take Poisson ration 0.3. a) determine specimen's new length after deformation. b) determine specimen's new diameter after deformation. Make sure to include the calculation for all steps including E and longitudinal and lateral strains MPа 700 600 500 400 300 200 100 10 15 E 10-3 (Ans:lnew - 46.718mm, Dnew - 9.885mm, )

3. The elastic portion of the stress-strain diagram for a titanium alloy used for medical implants shown. The specimen from which it was obtained has an original diameter of 10 mm and a gage length of 45 mm. If a tensile load of P = 300 kN is applied to the specimen. Take Poisson ration 0.3. a) determine specimen's new length after deformation. b) determine specimen's new diameter after deformation. Make sure to include the calculation for all steps including E and longitudinal and lateral strains MPа 700 600 500 400 300 200 100 10 15 E 10-3 (Ans:lnew - 46.718mm, Dnew - 9.885mm, )

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A tension test was performed on a steel specimen having an original diameter of 12.5 mm and gauge length of 50 mm. The data is listed in the table. Plot the stress–strain diagram and determine approximately the modulus of elasticity, the yield stress, the ultimate stress, and the rupture stress. Use a scale of 25 mm = 140 MPa and 25 mm = 0.05 mm/mm. Redraw the elastic region, using the same stress scale but a strain scale of 25 mm = 0.001 mm/mm.
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 150 kN. - Length of the specimen is 24 mm. - The yield strength is 78 kN/mm2. - The percentage of elongation is 42 %. Determine the following iii) Stress under an elastic load of 14 kN, iv) Young's Modulus if the elongation is 1.7 mm at 14 kN and (v) Final diameter if the percentage of reduction in area is 26 %. I wont answer for this three questions only: 1)Final Area of the Specimen at Fracture (in mm) 2)Final Diameter of the Specimen after Fracture (in mm) 3)Initial Cross-sectional Area (in mm2)
In a standard tensile test a steel rod of 7/8 in. in diameter is subjected to a tension force of 17 kips. Determine the ratio of the shear modulus to the modulus of elasticity of a material whose Poisson's ratio is 0.25.
How can I solve for the %0.2 offset strain and the calculated stress? Original diameter : 6mm Original length : 30mm Fracture diameter : 4.54mm
A rod with diameter 12mm is initially measured and market at exactly 250mm apart. This material has an ultimate of 400MPa. After a tensile load applied, distance between the marks was measured to be 250.26mm. E= 200GPa Determine : A. strain of the rod stress in the rod. B. the stress in the rod C. the factor of safety for the situation
A mild steel rod of 12mm diameter was tested for tensile strength with the gauge length of 60mm. After the test final length and the final diameter were 80mm and 7mm, respectively. Find the strain in the transverse direction
A cylindrical specimen of a titanium alloy having original diameter of 2.96 mm experiences elasticdeformation when a tensile load of 2500 N is applied. Compute the maximum length of the specimenbefore deformation if the maximum allowable elongation is 0.43 mm. Note: Etitanium = 107 GPa.
stress-strain behavior for the brass specimen shown in Figure 6.12, determine the following: (a) The modulus of elasticity (b) The yield strength at a strain offset of 0.002 (c) The maximum load that can be sustained by a cylindrical specimen hav- ing an original diameter of 12.8 mm (0.505 in.) (d) The change in length of a specimen originally 250 mm (10 in.) long that is subjected to a tensile stress of 345 MPa (50,000 psi)
The data shown in the table below were obtained from a tensile test of high-strength steel. The test specimen had a diameter of 13mm and a gage length of 50mm. At fracture, the elongation between the gage marks was 3.0mm and the minimum diameter was 10.7mm. Plot the conventional stress-strain curve for the steel and determine the propotional limit, modulus of elasticity (i.e the slope of the initial part of the stress-strain curve), yield stress at 0.1% offset, ultimate stress, percent elongation in 50mm, and percent reduction area. TENSILE-TEST DATA Load(kN) Elongation(mm) 5 0.005 10 0.015 30 0.048 50 0.084 60 0.099 64.5 0.109 67.0 0.119 68.0 0.137 69.0 0.160 70.0 0.229 72.0 0.259 76.0 0.330 84.0 0.584 92.0 0.853 100.0 1.288 112.0 2.814 113.0 Fracture
A nylon string has a diameter of 2 mm, pulled by a force of 100 N. Determine the stress.
Given a example of copper specimen that has had a tensile test conducted on it. Diameter of 6.4mm Max force of 11112.5N Max extension of 7.79mm Calculate: 1) modulus of elasticity 2) tensile strength 3) the ductility, in percent elongation 4) yield strength at a strain of 0.002
Given the following stress-strain graph:a. is the modulus of elasticity of "A-514" greater, less or equal to the one of "A-572"?b. from the previous question, make an estimatio for both of them, check that the graphic comes in %c. If we were to test these materials in a universal tension equipment, which one would withstand more load?d. If we were to test these materials in a universal tension machine, which one would elongate the most before fracturing? would elongate the most before fracturing? e. Of the 6 materials shown, do any behave as brittle materials? f.