3. The two identical shafts, 1 and 2, are built into supports at their left ends. Gears mounted on their right ends engage a third gear that is attached to shaft 3. Determine the torques in shafts 1 and 2 when the 500 N -m torque is applied to shaft 3. 40 500 Nm 80 (2 60 Dimensions in mm

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.3.17P: A stepped shaft ABC consisting of two solid, circular segments is subjected to torques T}and...
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3. The two identical shafts, 1 and 2, are built into supports at their left ends. Gears mounted
on their right ends engage a third gear that is attached to shaft 3. Determine the torques
in shafts 1 and 2 when the 500N -m torque is applied to shaft 3.
40
500 Nm
80
Dimensions in mm
4. A 4-ft-long tube with the cross section shown in the figure is made of aluminum. Find the
torque that will cause a maximum shear stress of 10 000 psi. Use G = 4 x 106 psi for aluminum.
+4 in. →
0.04 in.
0.08 in.´
5. Two steel springs are arranged in series as shown. The upper spring has 36 turns of 100-mm-
diameter wire on a mean radius of 350 mm. The lower spring consists of 24 turns of 75-mm
diameter wire on a mean radius of 245 mm. If the ultimate shearing stress in either spring
must not exceed 692 MPa, (a) compute the maximum value of P and total elongation using
factor of safety equal to 1.5. (b) What is the equivalent spring constant? Use G = 83 GPa.
2 of 2
4 in.
wwwww.-
Transcribed Image Text:3. The two identical shafts, 1 and 2, are built into supports at their left ends. Gears mounted on their right ends engage a third gear that is attached to shaft 3. Determine the torques in shafts 1 and 2 when the 500N -m torque is applied to shaft 3. 40 500 Nm 80 Dimensions in mm 4. A 4-ft-long tube with the cross section shown in the figure is made of aluminum. Find the torque that will cause a maximum shear stress of 10 000 psi. Use G = 4 x 106 psi for aluminum. +4 in. → 0.04 in. 0.08 in.´ 5. Two steel springs are arranged in series as shown. The upper spring has 36 turns of 100-mm- diameter wire on a mean radius of 350 mm. The lower spring consists of 24 turns of 75-mm diameter wire on a mean radius of 245 mm. If the ultimate shearing stress in either spring must not exceed 692 MPa, (a) compute the maximum value of P and total elongation using factor of safety equal to 1.5. (b) What is the equivalent spring constant? Use G = 83 GPa. 2 of 2 4 in. wwwww.-
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