3.15 Consider the corrosion of elemental iron in anaerobic waters (Fe° oxidized to Fe2+). with the reduction of protons (H*) to form hydrogen gas(H,): Fe + 2H* = Fe²+ + H2(g) (a) From thermodynamic considerations, calculate the equilibrium constant K at 25°C. (b) For T = 25°C, pH = 10, and [Fe"] = 10¬³ M, at what partial pressure of H, does this reaçtion become unfavorable?

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Chapter23: Organic Polymers, Natural And Synthetic
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3.15 (a) and (b) please help!
3.15 Consider the corrosion of elemental iron in anaerobic waters (Fe° oxidized to Fe2+)
with the reduction of protons (H*) to form hydrogen gas(H,):
Fe + 2H+ =
Fe2+ + H2(g)
(a) From thermodynamic considerations, calculate the equilibrium constant K at
25°C.
(b) For T = 25°C, pH = 10, and [Fe2"] = 10¬³ M, at what partial pressure of H,
does this reaction become unfavorable?
Out) to nitrate (NO.) by molecular oxygen:
Transcribed Image Text:3.15 Consider the corrosion of elemental iron in anaerobic waters (Fe° oxidized to Fe2+) with the reduction of protons (H*) to form hydrogen gas(H,): Fe + 2H+ = Fe2+ + H2(g) (a) From thermodynamic considerations, calculate the equilibrium constant K at 25°C. (b) For T = 25°C, pH = 10, and [Fe2"] = 10¬³ M, at what partial pressure of H, does this reaction become unfavorable? Out) to nitrate (NO.) by molecular oxygen:
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