Calculate the equilibrium constant Kc for a reaction occurring at a temperature of 15 oC, and with a ΔGo of -45.3 kJ/mol. (Use R=8.314 J/mol⋅K and 273.00 for oC/K conversion)
Calculate the equilibrium constant Kc for a reaction occurring at a temperature of 15 oC, and with a ΔGo of -45.3 kJ/mol. (Use R=8.314 J/mol⋅K and 273.00 for oC/K conversion)
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 53QRT
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Question
Calculate the equilibrium constant Kc for a reaction occurring at
a temperature of 15 oC, and with a ΔGo of -45.3 kJ/mol.
(Use R=8.314 J/mol⋅K and 273.00 for oC/K conversion)
Expert Solution
Step 1
(a)
Given:
Temperature = 15 C
delta G = -45.3 kJ/mol
Step 2
The value of given temperature in Kelvin is,
T(K) = T( C) + 273
T(K) = 15 + 273
T(K) = 288 K.
Step 3
The relationship between Gibbs free energy change and equilibrium constant is,
Here, R is the universal gas constant (8.314 J/K mole and Keq is the equilibrium constant and T is the temperature in kelvin.
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