#16 from this handout
From Numerical Analysis 8th Edition by Richard Burden, Section 3.4
Consider the function f(x) = ex and x0 = 0, x1 = 0.25, x2 = 0.75, x3 = 1.0
Let the polynomial passing through the above points:
a0 = f(x0) = f (0) = e0 = 1
a1 = f(x1) = f (0.25) = e.25 = 1.2840
a2 = f(x2) = f (0.75) = e0.75 = 2.1170
a3 = f(x3) = f (1) = e 1 = 2.7182
we have n = 3
h0 = x1 – x0 = 0.25
h1 = x2 – x1 = 0.50
h2 = x3 – x2 = 0.25
Using the above conditions and ...
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