3:00LTEREAD & DO: Principles...5. A pair of non-identical genes is called..a. heterozygous b. homogenes c. heterogenes d. homozygousLABORATORY PROCEDURE:Complete these 5 genetic problems using the Punnett Square and submityour answers in "LAB REPORT: Principles ofInheritance" before the deadline1. What is the probability for a childto have a chin fissurefrom the following parents:Both parents are homozygous dominant for achin fissure geneMom's genotype?*NOTE: chin fissure is a dominant trait FDad's genotype?smooth chin is recessive fChoose One: Theprobability that the childwill have a chin fissure is:a) 100%b) 50%c) 25%d) 0%2.One parent is homozygous dominant and the other heterozygous dominant forchin fissure gene.**NOTE: chin fissure is a dominant trait Fsmooth chin is a recessive trait fMom's genotype?A. Probability that child will havea chin fissure?Dad's genotype?B. Probability that child will behomozygous dominant for a chinfissure?C. Probability that child will beheterozygous dominant for a chinfissure?D. Probability that child will behomozygous recessive for a7smooth chin?3. Both parents are heterozygous dominant for a chin fissure geneMom's genotype:Dad's genotype:A. Probability that child will havea chin fissure?B. Probability that child will behomozygous dominant for a chinfissure?C. Probability that child will beheterozygous dominant for a chinficeure2PreviousNextDashboardCalendarNotificationsInboxTo Do 3:00LTEREAD & DO: Principles...DaagonotypoTa chin fissure?B. Probability that child will behomozygous dominant for a chinfissure?C. Probability that child will beheterozygous dominant for a chinfissure?D. Probability that child will behomozygous recessive for asmooth chin?73. Both parents are heterozygous dominant for a chin fissure gene.Mom's genotype:Dad's genotypeA. Probability that child will havea chin fissure?B. Probability that child will behomozygous dominant for a chinfissure?C. Probability that child will beheterozygous dominant for a chinfissure?D. Probability that child will behomozygous recessive for asmooth chin?4. What is the probability that a child will be born with sickle-cell anemia if his motherand father are both heterozygous dominant for the hemoglobin's shape gene?Hnormal gene for hemoglobin's shape; Dominanta. 50% chanceb. 75% chanceh= abnormal gene for hemoglobin's shape, Recessivec. 25% chanced. 0% chanceNOTE: 2 copies of theabnormal gene are neededto get sickle-cell anemia5. What is the probability that a child will be born with sickle-cell anemia if his mother isheterozygous dominant and his father is homozygous dominant for the hemoglobin'sshape gene?H normal gene for hemoglobin's shape; dominanta. 50% chanceh abnormal gene for hemoglobin's shape; recessiveb. 75% chancec. 25% chanced. 0% chance8PreviousNextitDashboardCalendarNotificationsInboxTo Do

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Asked Oct 8, 2019
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3:00
LTE
READ & DO: Principles...
5. A pair of non-identical genes is called..
a. heterozygous b. homogenes c. heterogenes d. homozygous
LABORATORY PROCEDURE:
Complete these 5 genetic problems using the Punnett Square and submit
your answers in "LAB REPORT: Principles of
Inheritance" before the deadline
1. What is the probability for a child
to have a chin fissure
from the following parents:
Both parents are homozygous dominant for a
chin fissure gene
Mom's genotype?
*NOTE: chin fissure is a dominant trait F
Dad's genotype?
smooth chin is recessive f
Choose One: The
probability that the child
will have a chin fissure is:
a) 100%
b) 50%
c) 25%
d) 0%
2.
One parent is homozygous dominant and the other heterozygous dominant for
chin fissure gene.*
*NOTE: chin fissure is a dominant trait F
smooth chin is a recessive trait f
Mom's genotype?
A. Probability that child will have
a chin fissure?
Dad's genotype?
B. Probability that child will be
homozygous dominant for a chin
fissure?
C. Probability that child will be
heterozygous dominant for a chin
fissure?
D. Probability that child will be
homozygous recessive for a
7
smooth chin?
3. Both parents are heterozygous dominant for a chin fissure gene
Mom's genotype:
Dad's genotype:
A. Probability that child will have
a chin fissure?
B. Probability that child will be
homozygous dominant for a chin
fissure?
C. Probability that child will be
heterozygous dominant for a chin
ficeure2
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Next
Dashboard
Calendar
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3:00 LTE READ & DO: Principles... 5. A pair of non-identical genes is called.. a. heterozygous b. homogenes c. heterogenes d. homozygous LABORATORY PROCEDURE: Complete these 5 genetic problems using the Punnett Square and submit your answers in "LAB REPORT: Principles of Inheritance" before the deadline 1. What is the probability for a child to have a chin fissure from the following parents: Both parents are homozygous dominant for a chin fissure gene Mom's genotype? *NOTE: chin fissure is a dominant trait F Dad's genotype? smooth chin is recessive f Choose One: The probability that the child will have a chin fissure is: a) 100% b) 50% c) 25% d) 0% 2. One parent is homozygous dominant and the other heterozygous dominant for chin fissure gene.* *NOTE: chin fissure is a dominant trait F smooth chin is a recessive trait f Mom's genotype? A. Probability that child will have a chin fissure? Dad's genotype? B. Probability that child will be homozygous dominant for a chin fissure? C. Probability that child will be heterozygous dominant for a chin fissure? D. Probability that child will be homozygous recessive for a 7 smooth chin? 3. Both parents are heterozygous dominant for a chin fissure gene Mom's genotype: Dad's genotype: A. Probability that child will have a chin fissure? B. Probability that child will be homozygous dominant for a chin fissure? C. Probability that child will be heterozygous dominant for a chin ficeure2 Previous Next Dashboard Calendar Notifications Inbox To Do

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3:00
LTE
READ & DO: Principles...
DaagonotypoT
a chin fissure?
B. Probability that child will be
homozygous dominant for a chin
fissure?
C. Probability that child will be
heterozygous dominant for a chin
fissure?
D. Probability that child will be
homozygous recessive for a
smooth chin?
7
3. Both parents are heterozygous dominant for a chin fissure gene.
Mom's genotype:
Dad's genotype
A. Probability that child will have
a chin fissure?
B. Probability that child will be
homozygous dominant for a chin
fissure?
C. Probability that child will be
heterozygous dominant for a chin
fissure?
D. Probability that child will be
homozygous recessive for a
smooth chin?
4. What is the probability that a child will be born with sickle-cell anemia if his mother
and father are both heterozygous dominant for the hemoglobin's shape gene?
H
normal gene for hemoglobin's shape; Dominant
a. 50% chance
b. 75% chance
h= abnormal gene for hemoglobin's shape, Recessive
c. 25% chance
d. 0% chance
NOTE: 2 copies of the
abnormal gene are needed
to get sickle-cell anemia
5. What is the probability that a child will be born with sickle-cell anemia if his mother is
heterozygous dominant and his father is homozygous dominant for the hemoglobin's
shape gene?
H normal gene for hemoglobin's shape; dominant
a. 50% chance
h abnormal gene for hemoglobin's shape; recessive
b. 75% chance
c. 25% chance
d. 0% chance
8
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it
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3:00 LTE READ & DO: Principles... DaagonotypoT a chin fissure? B. Probability that child will be homozygous dominant for a chin fissure? C. Probability that child will be heterozygous dominant for a chin fissure? D. Probability that child will be homozygous recessive for a smooth chin? 7 3. Both parents are heterozygous dominant for a chin fissure gene. Mom's genotype: Dad's genotype A. Probability that child will have a chin fissure? B. Probability that child will be homozygous dominant for a chin fissure? C. Probability that child will be heterozygous dominant for a chin fissure? D. Probability that child will be homozygous recessive for a smooth chin? 4. What is the probability that a child will be born with sickle-cell anemia if his mother and father are both heterozygous dominant for the hemoglobin's shape gene? H normal gene for hemoglobin's shape; Dominant a. 50% chance b. 75% chance h= abnormal gene for hemoglobin's shape, Recessive c. 25% chance d. 0% chance NOTE: 2 copies of the abnormal gene are needed to get sickle-cell anemia 5. What is the probability that a child will be born with sickle-cell anemia if his mother is heterozygous dominant and his father is homozygous dominant for the hemoglobin's shape gene? H normal gene for hemoglobin's shape; dominant a. 50% chance h abnormal gene for hemoglobin's shape; recessive b. 75% chance c. 25% chance d. 0% chance 8 Previous Next it Dashboard Calendar Notifications Inbox To Do

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Expert Answer

Step 1

Since we are entitled to answer only first question, we’ll answer question 1 as you have not mentioned the question number you need help with. Please resubmit the question and specify the other question numbers you’d like to get answered.

Step 2

Two copies of each chromosome are present in every person. Further, each chromosome has two versions for every gene, which are termed as the alleles. Alleles can be recessive or dominant in nature. Dominant allele gets express even if its only one copy is present, while a recessive allele is expressed if its two copies are present.

Step 3

Given-

The dominant allele for chin fissure =F

The recessive allele for smooth chin = f

The chin fissure is a dominant trait.

...

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Parents (Father) FF (Mother) FF (Chin fissure) (Chin fissure) Gametes F and F F and F Making a Punnett square we get Gametes FF FF (Chin fissure) (Chin fissure) FF FF (Chin fissure) (Chin fissure)

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