3‑Methylbutanal undergoes an aldol reaction to form 3‑hydroxy‑2‑isopropyl‑5‑methylhexanal.Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and curved arrows Step 2: A second molecule of aldehyde isadded. Complete the structure and addcurved arrows.Step 1: Add curved arrows.Select Draw Rings MoreEraseHSelect Draw Rings MoreEraseCH: о :H+H,OH: о :HHStep 3: Complete the intermediate and add curvedarrows to form the final product.Select Draw Rings MoreEraseH: о :H.:0-HHHOH 10% NaOHH.5 °CHO

Answered: Image /qna-images/answer/03d8b165-efb4-4e22-8904-4b0ea506deed.jpg

3‑Methylbutanal undergoes an aldol reaction to form 3‑hydroxy‑2‑isopropyl‑5‑methylhexanal. Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and curved arrows

3‑Methylbutanal undergoes an aldol reaction to form 3‑hydroxy‑2‑isopropyl‑5‑methylhexanal. Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and curved arrows

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter16: Spontaneity Of Reaction

Section: Chapter Questions

Problem 93QAP

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Question

100%

3‑Methylbutanal undergoes an aldol reaction to form 3‑hydroxy‑2‑isopropyl‑5‑methylhexanal.

Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and curved arrows

Step 2: A second molecule of aldehyde is
added. Complete the structure and add
curved arrows.
Step 1: Add curved arrows.
Select Draw Rings More
Erase
H
Select Draw Rings More
Erase
C
H
: о :
H
+H,O
H
: о :
H
H
Step 3: Complete the intermediate and add curved
arrows to form the final product.
Select Draw Rings More
Erase
H
: о :
H.
:0-H
H
HO
H

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