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3SnCl4 + 4Al(C2H5)3 ----> 3Sn(C2H5)4 + 4AlCl3 1) In one experiment, 0.300 L of SnCl4 (d = 2.226 g/mL) was treated with 0.579 L of triethylaluminum (Al(C2H5)3); d = 0.835 g/mL). What is the theoretical yield in this experiment (mass of tetraethylstannane, Sn(C2H5)4)? 2) If 0.352 L of tetraethylstannane (d = 1.187 g/mL) were actually isolated in this experiment, what was the percent yield?

3SnCl4 + 4Al(C2H5)3 ----> 3Sn(C2H5)4 + 4AlCl3 1) In one experiment, 0.300 L of SnCl4 (d = 2.226 g/mL) was treated with 0.579 L of triethylaluminum (Al(C2H5)3); d = 0.835 g/mL). What is the theoretical yield in this experiment (mass of tetraethylstannane, Sn(C2H5)4)? 2) If 0.352 L of tetraethylstannane (d = 1.187 g/mL) were actually isolated in this experiment, what was the percent yield?

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter2: Atoms, Molecules, And Ions
Section: Chapter Questions
Problem 93QAP: Hydrogen gas is prepared in a lab experiment. In this experiment, 18.00 g of aluminum metal are...
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3SnCl4 + 4Al(C2H5)3 ----> 3Sn(C2H5)4 + 4AlCl3

1) In one experiment, 0.300 L of SnCl4 (d = 2.226 g/mL) was treated with 0.579 L of triethylaluminum (Al(C2H5)3); d = 0.835 g/mL).
What is the theoretical yield in this experiment (mass of tetraethylstannane, Sn(C2H5)4)?

2) If 0.352 L of tetraethylstannane (d = 1.187 g/mL) were actually isolated in this experiment, what was the percent yield?

 

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