3SnCl4 + 4Al(C2H5)3 3Sn(C2H5)4 + 4AlCl3 In one experiment, 0.150 L of SnCl4 (d = 2.226 g/mL) was treated with 0.317 L of triethylaluminum (Al(C2H5)3); d = 0.835 g/mL). What is the theoretical yield in this experiment (mass of tetraethylstannane, Sn(C2H5)4)?

3SnCl4 + 4Al(C2H5)3 3Sn(C2H5)4 + 4AlCl3 In one experiment, 0.150 L of SnCl4 (d = 2.226 g/mL) was treated with 0.317 L of triethylaluminum (Al(C2H5)3); d = 0.835 g/mL). What is the theoretical yield in this experiment (mass of tetraethylstannane, Sn(C2H5)4)?

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter21: The Chemistry Of The Main Group Elements

Section: Chapter Questions

Problem 120IL

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Stoichiometry

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3SnCl₄ + 4Al(C₂H₅)₃ 3Sn(C₂H₅)₄ + 4AlCl₃

In one experiment, 0.150 L of SnCl₄ (d = 2.226 g/mL) was treated with 0.317 L of triethylaluminum (Al(C₂H₅)₃); d = 0.835 g/mL).
What is the theoretical yield in this experiment (mass of tetraethylstannane, Sn(C₂H₅)₄)?

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3SnCl4 + 4Al(C2H5)3 ----> 3Sn(C2H5)4 + 4AlCl3 A) In one experiment, 0.300 L of SnCl4 (d = 2.226 g/mL) was treated with 0.579 L of triethylaluminum (Al(C2H5)3); d = 0.835 g/mL). What is the theoretical yield in this experiment (mass of tetraethylstannane, Sn(C2H5)4)? B) If 0.352 L of tetraethylstannane (d = 1.187 g/mL) were actually isolated in this experiment, what was the percent yield?
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