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4) When 0.250 mole of CO2 (g) is placed in a 1.0 L container, some of it decomposes according to the reaction 2 CO (g) + O2(g) If the equilibrium concentration of CO is 0.040 M, the Key for the reaction must be a. 4.4 x 10¹¹ c. 9.8 x 107 d. 1.7 x 10¹ 2 CO₂)->> b. 1.2 x 10² e. 7.3 x 104

4) When 0.250 mole of CO2 (g) is placed in a 1.0 L container, some of it decomposes according to the reaction 2 CO (g) + O2(g) If the equilibrium concentration of CO is 0.040 M, the Key for the reaction must be a. 4.4 x 10¹¹ c. 9.8 x 107 d. 1.7 x 10¹ 2 CO₂)->> b. 1.2 x 10² e. 7.3 x 104

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter13: Fundamental Equilibrium Concepts
Section: Chapter Questions
Problem 92E: Antimony pentachloride decomposes according to this equation: SbCl5(g)SbCl3+Cl2(g) An equilibrium...
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4) When 0.250 mole of CO2 (g) is placed in a 1.0 L container, some of it decomposes according to the reaction 2 CO(g) + O2(g) 6670 720 If the equilibrium concentration of CO is 0.040 M, the Key for the reaction must be a. 4.4 x 10¹ c. 9.8 x 10-7 d. 1.7 x 10 2 CO₂(e)-> b. 1.2 x 102 e. 7.3 x 104
Transcribed Image Text:4) When 0.250 mole of CO2 (g) is placed in a 1.0 L container, some of it decomposes according to the reaction 2 CO(g) + O2(g) 6670 720 If the equilibrium concentration of CO is 0.040 M, the Key for the reaction must be a. 4.4 x 10¹ c. 9.8 x 10-7 d. 1.7 x 10 2 CO₂(e)-> b. 1.2 x 102 e. 7.3 x 104
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